CODEWITHSUNDEEP
c++arrays
URL87
URL87

Reputation: 11012

set array elements using new

There is that way to set elements on array - int rgArrayNum [] = {16, 2, 77, 40, 12071}; How can I do same way on pointer with new ? I tried int *pArrayNum = new [] = {4 ,3 ,3} ; but it didn't worked .

Upvotes: 0

Views: 98

Answers (3)

ecatmur
ecatmur

Reputation: 157334

In , you can write:

int *pArrayNum = new int[3]{4, 3, 3};

However, in array new initialization is not allowed; you'd have to initialize the members individually or by copy from an array on the stack:

int rgArrayNum [] = {16, 2, 77, 40, 12071};
int *pArrayNum = new int[sizeof rgArrayNum / sizeof rgArrayNum[0]];
std::copy(&rgArrayNum[0], &rgArrayNum[sizeof rgArrayNum / sizeof rgArrayNum[0]],
    pArrayNum);

Upvotes: 7

Giel
Giel

Reputation: 397

You have to create the array not with integers but with integer pointers.

int* rgArrayNum2 [] = {new int(16), new int(16), new int(16), new int(16), new int(16)};

//test
int* test = rgArrayNum2[2];
*test = 15;

now rgArrayNum2[2] is 15.

Upvotes: 0

Mike Seymour
Mike Seymour

Reputation: 254431

In C++03 and earlier, you can't initialise the values of a dynamic array to anything except zero.

You can achieve something similar in C++11:

int *pArrayNum = new int [3] {4, 3, 3};

or if you don't mind using a container to manage the memory for you:

std::vector<int> array = {4, 3, 3};

Upvotes: 3

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