CODEWITHSUNDEEP
phpreplace
ajdi
ajdi

Reputation: 454

Remove token variables

I'm in the process of writing a theme based script and need a way to replace "variables" or tokens that weren't replaced by the script.

The format is:

^_variablename_^

So say, after processing the following, with variables: name=Adam, Occupation=programmer

Hello, my name is ^_title_^^_name_^, and I work as a ^_occupation_^.

We'd be left with ^_title_^ still in place.

I need a way to get rid of these, without knowing the name of the "variable".

Thanks in advance :)

Upvotes: 0

Views: 84

Answers (3)

complex857
complex857

Reputation: 20753

Try using preg_replace_callback, when substitute variables in so you can simply ignore ones you can't substitute in:

$input = 'Hello, my name is ^_title_^^_name_^, and I work as a ^_occupation_^.  ';
$variables = array('name' => 'adam');
$re = preg_replace_callback('/\^_(?<var>.+?)_\^/', function($params) use ($variables) {
        if (isset($variables[$params['var']])) {
            return $variables[$params['var']]; 
        } else {
            return '';
        }   
    },  
$input);

print $re;

This uses anonymous function syntax that works since php 5.3.0, you might need to declare a separate callback for this if you want to use it on earlier versions.

Upvotes: 0

Sergii Stotskyi
Sergii Stotskyi

Reputation: 5390

$str = 'Hello, my name is ^_title_^Adam, and I work as a programmer.';
echo preg_replace('/^_[\w_-]+_^/i', '', $str);

Upvotes: 0

Mihai Iorga
Mihai Iorga

Reputation: 39724

Process again:

$str = 'Hello, my name is ^_title_^Adam, and I work as a programmer.';
$str = preg_replace('/\^_(\w+)_\^/', '', $str);

echo $str;

Codepad

Upvotes: 1

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