CODEWITHSUNDEEP
bash
Arnaud Courtecuisse
Arnaud Courtecuisse

Reputation: 367

How can I pass quoted parameters from a function to another?

I'm having a little issue with a script I'm writing... let's say I have 2 functions :

function foo1 {
    while [ $# -gt 0 ]; do
        echo $1
        shift
    done
}

function foo2 {
    foo1 $@
}

My problem is the following. If I do foo1 -o "file with space.txt" output is

-o
file with space.txt

But with foo2 -o "file with space.txt" or foo2 -o file\ with\ space.txt, I get

-o
file
with
space.txt

Is there any way that foo1 receives "file with space.txt" from foo2 ?

Upvotes: 0

Views: 69

Answers (1)

choroba
choroba

Reputation: 241748

In function foo2, use double quotes:

foo1 "$@"

See man bash for details:

When the expansion occurs within double quotes, each parameter expands to a separate word. That is, "$@" is equivalent to "$1" "$2"

Upvotes: 5

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