Reputation: 36422
I am using Jqgrid with a custom button column. I using jqgrid's load complete method to populate the button. Below the code I use in load complete.
var grid = $("#grid"),
iCol = getColumnIndexByName(grid,'custom'); // 'custom' - name of the actions column
grid.children("tbody")
.children("tr.jqgrow")
.children("td:nth-child("+(iCol+1)+")")
.each(function() {
$("<div>",
{
title: "button1",
mouseover: function() {
$(this).addClass('ui-state-hover');
},
mouseout: function() {
$(this).removeClass('ui-state-hover');
},
click:
handle your click function here
}
).css({"margin-left": "5px", float:"left"})
.addClass("ui-pg-div ui-inline-save")
.attr('id',"customId")
.append('<span class="ui-button-icon-primary ui-icon ui-icon-disk"></span>')
.appendTo($(this).children("div"));
)};
var getColumnIndexByName = function(grid,columnName) {
var cm = grid.jqGrid('getGridParam','colModel'), i=0,l=cm.length;
for (; i<l; i+=1) {
if (cm[i].name===columnName) {
return i; // return the index
}
}
return -1;
};
It displays buttons in all the rows. But I want to get it displayed only in few rows based on the value from first and second column. Is there any easy way where i can get the first and second column values or I need to iterate again over "tbody" and retrieve the results ? Please help me out.
Upvotes: 0
Views: 1105
Reputation: 5238
You should check out custom formatters.
In a column you can define a formatter in the colmodel that triggers for each row of the grid. Then you can do the following:
function formatterName(cellvalue, rowid, rowObject)
{
if(rowObject[1] == "YourValue" && rowObject[2] == "YourValue"){ // index for choosing which column to check
// run code for displaying buttons in the columns that matches your criteria
}
}
Upvotes: 1