CODEWITHSUNDEEP
phpformspost
user984187
user984187

Reputation:

php _POST random not working

I have a strange problem.

Situation: I have a form with the method 'post'. Inside that form I have 1 checkbox and a submit button. When i press the submit button an if statement will catch wether the post var is isset.

Problem: When i press the submit button, it randomly doesn't work. So I press it now and it works or it won't.

Here is the code I use to catch the post

if ( isset ( $_POST['mail_subscribe'] )  ) {
    //My code here
}

And here is the code from the form (I'm using smarty)

<form action="/my/url.html" method="post">
    <input type="checkbox" name="mail_subscribe" class="mail_subscribe" id="{$var.graph1.ID}" {if $var.mailing == 1}checked="checked" value="0"{else}value="1"{/if} />
    <br /><br />
    <input type="submit" value="save" id="mailing_submit"/>
</form>

When i submit this form sometimes it works and more often it doesn't. If you guys need more information let me know. I'll update the question asap.

ANSWER

I found the answer to my problem. Thank you @RobertMaysJr for that.

When a checkbox is not checked, and it is the only field inside the form, the form will never submit.

Now that I know that I'm changing the way I'll be doing this :)

Upvotes: 0

Views: 222

Answers (6)

jacky
jacky

Reputation: 171

use this jquery is easier 

$('#yourcheckbox').click(function(){
  if($(this).is(':checked')){
       $.post('http://your form action url',{your form data },function(result){
               alert(result);
       }
  }

});

I have random post data method which replace all your form data into fake data during send read here http://www.jackart4.com/article.html

Upvotes: 0

Poonam
Poonam

Reputation: 4631

instead of checking checkbox value check for submit button

if ( isset ( $_POST['mail_subscribe'] )  ) {
    //My code here
}

instead of that check

if ( isset ( $_POST['mailing_submit'] )  ) {
    //My code here
}

this will ensure form submission. if checkbox is checked then only your code will work

Upvotes: 0

user1647981
user1647981

Reputation:

shouldn't your form action should have .php extension file:

<form action="/my/url.php" method="post">
    <input type="checkbox" name="mail_subscribe" class="mail_subscribe" id="{$var.graph1.ID}" {if $var.mailing == 1}checked="checked" value="0"{else}value="1"{/if} />
    <br /><br />
    <input type="submit" value="save" id="mailing_submit" name="mailing_submit"/>
</form>

And

if ( isset($_POST['mailing_submit'])  ) {
  //your code here
}

Upvotes: 0

Ashwini Agarwal
Ashwini Agarwal

Reputation: 4858

use this...

if ( isset ( $_POST['mailing_submit'] )  ) {
    //My code here
}

And

<form action="/my/url.html" method="post">
    <input type="checkbox" name="mail_subscribe" class="mail_subscribe" id="{$var.graph1.ID}" {if $var.mailing == 1}checked="checked" value="0"{else}value="1"{/if} />
    <br /><br />
    <input type="submit" value="save" id="mailing_submit" name="mailing_submit"/>
</form>

Upvotes: 1

Jocelyn
Jocelyn

Reputation: 11413

The problem is that the key mail_subscribe will exist in $_POST only when the checkbox is checked.

So, the code will not execute all the time.

Upvotes: 0

msEmmaMays
msEmmaMays

Reputation: 1063

it needs to always be value="1" - if the checkbox is not checked then it won't be submitted at all by the browser

Upvotes: 0

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