Reputation: 277
I'm trying to figure out how I can output the string of text Try this recipe
at the beginning of this twitter sharing function. So when you click the button to share it will say "Try this recipe" then have the url etc. Thank you.
function load_twitter() {
var load = window.open('http://twitter.com/share?url='+ window.location.href +'&via=atsbyvermouth','','scrollbars=no,menubar=no,height=450,width=650,resizable=yes,toolbar=no,location=no,status=no');
}
Upvotes: 2
Views: 1290
Reputation: 146219
It's very simple, just add this text=Try this recipe&
at first, i.e.
function load_twitter() {
window.open('http://twitter.com/share?text=Try this recipe&url='+ window.location.href +'&via=atsbyvermouth','','scrollbars=no,menubar=no,height=450,width=650,resizable=yes,toolbar=no,location=no,status=no');
}
DEMO.
Upvotes: 2