CODEWITHSUNDEEP
javastring
The Learner
The Learner

Reputation: 3917

java search for a particular word in a string

I have string like:

This.is.a.great.place.too.work.

(or)

This/is/a/great/place/too/work/

I want to see if this string has the word "place".

If they are word in a string I used contains("place"). as this is all one string I tried split but it is giving syntax error . can you please let me know how to get it?

string.contains("place") works
String.split(".").contains("place")   Error

Upvotes: 0

Views: 1266

Answers (7)

abhi
abhi

Reputation: 347

try this 

string.split(pattern);
String[] strings = s.split(".")

Split will give array of strings which are splitted based on the paramater .

you cannot apply contains on string array , instead use the following 

boolean flag = string.contains("required_pattern");

Upvotes: 1

Kumar Vivek Mitra
Kumar Vivek Mitra

Reputation: 33534

Try it simply like this.......

String s = "This/is/a/great/place/too/work/";
String ss = "This.is.a.great.place.too.work";

System.out.println(s.contains("place"));
System.out.println(ss.contains("place"));

Upvotes: 1

npinti
npinti

Reputation: 52185

Besides using the .contains method, which I think is best, you seem to want to build a data structure and search through it. To do something like that, you will need to do this:

String str = "This.is.a.great.place.too.work.";
String[] splitWords = str.split("\\.");  //The . is a special character in regex language, thus needs to be escaped. Alternatively you could use \\W which will split the string where ever it finds a character which is not a letter, digit or underscore.
List<String> words = Arrays.asList(splitWords);
System.out.println(words.contains("place"));

Alternatively, you could use the indexOf(String str) method like so:

if (str.indexOf("place") > 0)
{
    System.out.println("String Exists");
}

Upvotes: 1

Jason
Jason

Reputation: 1241

Try to split with "//."

    String string = "This.is.a.great.place.too.work.";
    System.out.println(string.split("\\.")[0]);

Upvotes: 2

RP-
RP-

Reputation: 5837

use string.split("\\.").contains("place") this should work. .(dot) is a reserved character in regular expression, You need to escape that by using \\..

Upvotes: 2

CloudyMarble
CloudyMarble

Reputation: 37566

you dont need to split the string in order to use the containts methode.

string str = "This.is.a.great.place.too.work.";

boolean found = str.contains("substring"); // should return true or false

Alternative you can use the:

str.indexOf("substring") > 0 to determine if the substring is in the string

To do this in one single line you can do something like:

Arrays.toString(str.split(".")).Contains("substring")

Upvotes: 1

MaVRoSCy
MaVRoSCy

Reputation: 17839

you can use

String str = "This.is.a.great.place.too.work.";
boolean exists = str.contains("place");

This checks to find the word place in a String and returns true if found, false if not

Upvotes: 1

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