Reputation: 267
In Oracle how do I find Cars which must have Feature1 and have at lest, one out of Feature2 or Feature3. Sample table and expected result should look like below screenshot. Thanks Kiran
Upvotes: 0
Views: 446
Reputation: 1269483
I like to do this with GROUP BY and HAVING:
select car
from t
group by car
having max(case when feature = 'Feature1' then 1 else 0 end) = 1 and
max(case when feature in ('Feature1', 'Feature2') then 1 else 0 end) = 1
This query returns the cars. To get the featuers as well, you have to join tis back in:
select t.*
from (select car
from t
group by car
having max(case when feature = 'Feature1' then 1 else 0 end) = 1 and
max(case when feature in ('Feature1', 'Feature2') then 1 else 0 end) = 1
) c join
t
on t.car = c.car
I like this method, because the same idea can be used for handling many different similar queries -- AND conditions, OR conditions, different subgroups, and different counts.
Upvotes: 0
Reputation: 247630
This should work:
select t1.car, t1.feature
from yourtable t1
inner join
( -- inner select returns the cars with the Feature1 and Feature2 or Feature3
select car, feature
from yourtable
where feature = 'Feature1'
and exists (select car
from yourtable
where feature in ('Feature2', 'Feature3'))
) t2
on t1.car = t2.car
where t1.feature in ('Feature1', 'Feature2', 'Feature3') -- this excludes any other features
Upvotes: 1