CODEWITHSUNDEEP
python
iamauser
iamauser

Reputation: 11469

create dictionary with multiple keys and values

I would like to create a dictionary with multiple keys and values. At this point I am not sure that I am putting my question correctly. But here is an example of what I want to create :

patDct = {
           'mkey1':{'key1':'val_a1', 'key2':'val_a2', 'key3':'val_a3'},
           'mkey2':{'key1':'val_b1', 'key2':'val_b2', 'key3':'val_b3'},
           ....
          }

I have two dictionaries and I am pulling information for 'mkey*', and 'val*' from them. 'key*' are strings.

I have a piece of code to create the dictionary without the 'mkey*', but that only prints out the last set of values. Following is what I have now. "storedct" and "datadct" are two given dictionaries. Here I would like 'mkey*' to get the value of "item".

 patDct = dict()                                                                                                                                                             
 for item in storedct :                                                                                                                                                         
     for pattern in datadct :                                                                                                                                                    
         if pattern in item :                                                                                                                                                     
             patDct['key1'] = datadct[pattern]["dpath"]                                                                                                        
             patDct['key2'] = datadct[pattern]["mask"]                                                                                                                                                                                                                                                
             patDct['key3'] = storedct[item]

Thanks for any suggestion.

Upvotes: 0

Views: 362

Answers (2)

Emmanuel
Emmanuel

Reputation: 14209

From what I understand from your code, I guess that:

patDct = dict()
i = 0
for item in storedct :
    for pattern in datadct :
        if pattern in item :
            i = i + 1
            new_item = {}
            new_item['key1'] = datadct[pattern]["dpath"]
            new_item['key2'] = datadct[pattern]["mask"]
            new_item['key3'] = storedct[item]
            # I used a counter to generate the `mkey` values,
            # not sure you want it that way
            patDct['mkey{0}'.format(i)] = new_item

should not be far from your needs...

Upvotes: 1

Joran Beasley
Joran Beasley

Reputation: 113930

 patDct = dict()    
 n=1                                                                                                                                                        
 for item in storedct :
     patDct["mkey%s"%n] = {}
     p =  patDct["mkey%s"%n]                                                                                                                                                            
     for pattern in datadct :                                                                                                                                                    
         if pattern in item :                                                                                                                                                     
             p['key1'] = datadct[pattern]["dpath"]                                                                                                        
             p['key2'] = datadct[pattern]["mask"]                                                                                                                                                                                                                                                
             p['key3'] = storedct[item] 
     n +=1

print patDct

Upvotes: 1

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