CODEWITHSUNDEEP
c++
Intelwalk
Intelwalk

Reputation: 671

addition operator has no affect

I am trying to add two floats in a for loop and its telling me '+' has no affect. I am attempting to make it parse through each incrememnt (.25) of the two ranges (begrate and endrate) (1 and 2) and 1+.25 is not working correctly and I get an infinite loop

float begrate,endrate,inc,year=0;

cout << "Monthly Payment Factors used in Compute Monthly Payments!" << endl;
cout << "Enter Interest Rate Range and Increment" << endl;
cout << "Enter the Beginning of the Interest Range:  ";
cin >> begrate;
cout << "Enter the Ending of the Interest Range:  ";
cin >> endrate;
cout << "Enter the Increment of the Interest Range:  ";
cin >> inc;
cout << "Enter the Year Range in Years:  ";
cin >> year;

cout << endl;

for (float i=1;i<year;i++){
    cout << "Year:  " << "     ";
    for(begrate;begrate<endrate;begrate+inc){
        cout << "Test " << begrate << endl;
    }
}
system("pause");
return 0;

Upvotes: 0

Views: 148

Answers (3)

scleaver
scleaver

Reputation: 246

You could use += instead of +, as this will set begrate to begrate+inc. The better solution would be to have a temporary loop variable that starts equal to begrate then increment it.

for (float i=1;i<year;i++){
    cout << "Year:  " << "     ";
    for(float j = begrate;j<endrate;j+=inc){
        cout << "Test " << j << endl;
    }
}

Upvotes: 4

Murtuza Kabul
Murtuza Kabul

Reputation: 6514

Just replace the following line

for(begrate;begrate<endrate;begrate+inc){


with

for(begrate;begrate<endrate;begrate+=inc){

notice the begrate*+=*inc here

Upvotes: 3

Carey Gregory
Carey Gregory

Reputation: 6846

That's because begrate+inc has no effect on the value of begrate. The + operator is not like the ++ operator. You must assign the results to something to have an effect. What you wanted is this:

begrate = begrate + inc

Or

begrate += inc

Upvotes: 7

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