CODEWITHSUNDEEP
djangofiledjango-modelsfilefield
aemdy
aemdy

Reputation: 3802

Renaming files in Django FileField

I know that there is a very similar thread here, but I cannot find the solution to my problem.

I need to rename a file which is save in django models.FileField

I tried this

os.rename(old_path, new_path)
mod.direct_file = File(open(new_path))
mod.save()

And this

mod.direct_file.save(new_path, File(open(old_path)))
os.remove(old_path)

And many other ways, but nothing seemed to help. A new file is created in all ways, however, data in filefield does not change at all.

EDIT: SOLVED

os.rename(old_path, new_path)
cursor = connection.cursor()
cursor.execute("UPDATE mods_mod SET direct_file = %s WHERE id = %s", [new_name, mod.id])
transaction.commit_unless_managed()

Upvotes: 14

Views: 16948

Answers (6)

JMJ
JMJ

Reputation: 2162

It seems changing filename of a binary in FileField is pretty unflexible according to the django docs. It contains the path from Media root. That points out to a name attr that is reflecting the path, not just the filename itself. Docs: This is the way that django model can find the file

Upvotes: 0

user8446586
user8446586

Reputation: 11

You may use the following:

Suppose 'obj' is the django object that you want to rename. Then do this:

obj.file_field_name.name = new_name

obj.save()

Upvotes: 1

miigotu
miigotu

Reputation: 1715

I came across this issue when I had blobs saved into django with no file extension, and I wanted to correct that. Best used when looping over a filtered queryset.

You cannot change instance.picture.path, and trying to access instance.picture.file.* will give an error because accessing it will try to open the old file. Setting instance.picture.name will still not let you access instance.picture.file.*, even after saving.

You can simply set the ImageField object itself to the location and all will work:

(Tested with django 1.10)

import imghdr
import os

from django.db import models

class MyModel(models.Model):
    picture = models.ImageField()

instance = MyModel.objects.first()
if os.path.exists(instance.picture.path):
    extension = imghdr.what(instance.picture.path)
    os.rename(instance.picture.path, instance.picture.path + '.' + extension)
    instance.picture = instance.picture.name + '.' + extension
    instance.save()

Upvotes: 2

Javier Gutierrez
Javier Gutierrez

Reputation: 559

 new_name = 'photos_preview/' + str(uuid.uuid1())
 os.rename(photo.image_preview.path, settings.MEDIA_ROOT + new_name)
 photo.image_preview.name = new_name
 photo.save()

Upvotes: 5

Brian Neal
Brian Neal

Reputation: 32399

I don't think you need to use raw SQL for this. I think you need to rename the file using the os facility, then set the model's FileField name to the new name. Maybe something like:

os.rename(model.direct_file.path, new_path)
model.direct_file.name = new_name
model.save()

Upvotes: 18

droxey
droxey

Reputation: 84

The current Django documentation states:

"When you access a FileField on a model, you are given an instance of FieldFile as a proxy for accessing the underlying file." See docs for further reading.

Instead of using the Python File object to open the file, you should use FieldFile.open() to open the file, then manipulate the file's path accordingly. Afterward, save the model object, and the changes to the path should persist.

Upvotes: 3

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