CODEWITHSUNDEEP
javaoverloading
Tushar Paliwal
Tushar Paliwal

Reputation: 301

Method overloading with argument vararg of object class and array of object class

If I attempt to overload the method flexiPrint() in a class Varargdemo then it generates a compile time error. The compiler treats the following signatures the same:

public static void flexiPrint(Object... data){}
public static void flexiPrint(Object[] data){}

Can someone explain to me why they are treated the same? I haven't been able to find the answer.

Upvotes: 2

Views: 302

Answers (3)

bfishman
bfishman

Reputation: 579

Variable Length Arguments, like Object... are syntactic sugar. When used, for example:

flexiPrint("apple", "peach", "plum");

Then "apple", "peach", "plum" are actually turned into: `Object[]{"apple", "peach", "plum"}.

Upvotes: 2

S.L. Barth is on codidact.com
S.L. Barth is on codidact.com

Reputation: 8255

They are the same "under the hood". varargs (the ...) passes an array as a parameter:

It is still true that multiple arguments must be passed in an array, but the varargs feature automates and hides the process. Furthermore, it is upward compatible with preexisting APIs.

You can find it in the documentation here .

Upvotes: 3

kosa
kosa

Reputation: 66657

Object... is nothing but it is an array, that means same as defining Object[]

... (three dots) represents varargs in java.

We usually see this signature in main method like main(String... args)

So, having more than one method with same signature is not allowed in a class (compile time error). That is why you are seeing compile time error.

Upvotes: 3

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