Reputation: 665
I have a function foo
that only stops once a condition has been met. While foo
is running, I need to ask for user input the whole time (keeps asking for user input). I want them to run separately without interfering with each other.
In my example below, foo
keeps printing 'Hello' and getUserInput
keeps looking for user input. I want foo to keep printing hello even if i do not enter anything for user input. It will keep asking for input as long as the user does not enter letter 'e'. I have my attempt below:
import threading
from time import sleep
class test:
def __init__(self):
self.running = True
def foo(self):
while(self.running):
print 'Hello\n'
sleep(2)
def getUserInput(self):
x = ''
while(x != 'e'):
x = raw_input('Enter value: ')
self.running = False
def go(self):
th1 = threading.Thread(target=self.foo)
th2 = threading.Thread(target=self.getUserInput)
th1.start()
th2.start()
t = test()
t.go()
My code prints out the first hello and asks for input but nothing after that. What am I doing wrong? Thanks for your help in advance.
Upvotes: 6
Views: 11799
Reputation: 35761
Update: The opener was running his code on Windows in IDLE. Regarding I/O it behaves differently than a shell or the Windows command line. His code works on the Windows command line.
In principle, your code works for me. I am running Python 2.6.5.
Several comments here:
1) In your case it would be fine to only have two threads: the main thread and another one. However, it will also work with three. It's just that your main thread does nothing else than waiting for the other threads to finish.
2) You should to explicitly join()
all threads you spawn. You do this in the main thread before terminating it. Keep record of the threads you spawn (e.g. in a list threads
) and then join them at the end of your program (e.g. for t in threads: t.join()
).
3) You share the variable self.running
between threads. It is fine in this case, as one thread only reads it and another one only writes it. In general, you need to be very careful with shared variables and acquire a lock before changing it.
4) You should catch the KeyboardInterrupt
exception in the main thread and find a way to communicate to your other threads to terminate :)
5) Use lowercase method names, so instead of getUserInput
call it get_user_input
. Use uppercase class names and inherit from object
: class Test(object):
This is a running example:
import threading
from time import sleep
def main():
t = Test()
t.go()
try:
join_threads(t.threads)
except KeyboardInterrupt:
print "\nKeyboardInterrupt catched."
print "Terminate main thread."
print "If only daemonic threads are left, terminate whole program."
class Test(object):
def __init__(self):
self.running = True
self.threads = []
def foo(self):
while(self.running):
print '\nHello\n'
sleep(2)
def get_user_input(self):
while True:
x = raw_input("Enter 'e' for exit: ")
if x.lower() == 'e':
self.running = False
break
def go(self):
t1 = threading.Thread(target=self.foo)
t2 = threading.Thread(target=self.get_user_input)
# Make threads daemonic, i.e. terminate them when main thread
# terminates. From: http://stackoverflow.com/a/3788243/145400
t1.daemon = True
t2.daemon = True
t1.start()
t2.start()
self.threads.append(t1)
self.threads.append(t2)
def join_threads(threads):
"""
Join threads in interruptable fashion.
From http://stackoverflow.com/a/9790882/145400
"""
for t in threads:
while t.isAlive():
t.join(5)
if __name__ == "__main__":
main()
When typing e or E, the program ends after a short delay (as intended by you). When pressing ctrl+c, it immediately terminates. Making a program that uses threading
responsive to exceptions is a bit trickier than expected. I have included important references in the source above.
This is how it looks like during runtime:
$ python supertest.py
Hello
Enter 'e' for exit:
Hello
Hello
Hello
e
$
Upvotes: 7