CODEWITHSUNDEEP
ajaxcoldfusionmodel-glue
ajithmanmu
ajithmanmu

Reputation: 1169

Ajax call in ModelGlue ColdFusion Application without rendering a view

I am using Ajax with ModelGlue in a ColdFusion Application. I want to make an Ajax call to return a value. I do not want to render any view. I just want a database interaction and bring back a value.

My Ajax call:

new Ajax.Request(root+'test.testFunction',{
  method: 'post',
  parameters: {param1:paramval},
  onSuccess: function(response){
    alert(response.responseText);
    var myresult = response.responseText;
  }
});

my modelglue event :

<event-handler name="test.testFunction">
     <broadcasts>
          <message name="testFunction" />
     </broadcasts>
</event-handler>

and my controller function:

<cffunction name="testFunction" returnType="any" output="true" >
     <cfargument name="event" type="any" required="true">
        <cfset justtest = 1>
     <cfreturn justtest>
</cffunction>

I am using prototype as my ajax library.

When i alert the responseText i am getting null value. Is this bcoz i have not included the view part in the event handler? If i included the view part then i wud have to create a new page which i dont want to do. Is it possible to get just a server value by ajax call without rendering any view? I want to have myresult value as 1 according to the above scenario.

Pls help. Thnx for any help.

Upvotes: 1

Views: 789

Answers (4)

user778574
user778574

Reputation: 53

WARNING: if Coldfusion 8, and have OnRequest() in application.cfc, there may be a related known cf8 bug. For a workaround, see http://www.coldfusionjedi.com/index.cfm/2008/3/19/Ask-a-Jedi-Ajaxbound-requests-and-onRequest

Upvotes: 0

Masterbuddha
Masterbuddha

Reputation: 632

Try using this at the end of your controller function:

<CFCONTENT TYPE="text" RESET="Yes"><CFOUTPUT>#serializeJSON(justTest)#
<cfset request.modelGlueSuppressDebugging = true />
<cfsetting showdebugoutput="false" /></CFOUTPUT><cfabort>

So like this:

<cffunction name="testFunction" returnType="any" output="true" >     
<cfargument name="event" type="any" required="true">        

<cfset justtest = 1>

<CFCONTENT TYPE="text" RESET="Yes"><CFOUTPUT>#serializeJSON(justTest)#
<cfset request.modelGlueSuppressDebugging = true />
<cfsetting showdebugoutput="false" /></CFOUTPUT><cfabort>

</cffunction>

This will keep your current view and return 'justTest' as a json.

If you are using firefox you should be able to see the reponse from the server.

Upvotes: 1

Henry
Henry

Reputation: 32915

In this situation, you should really be calling the remote proxy of your service, bypassing the MVC framework. :)

Oh, and don't forget you can use <cfajaxproxy> if you're using CF8.

Upvotes: -1

Adam Tuttle
Adam Tuttle

Reputation: 19834

When you say you "just want to bring back a value" -- that's your "view". What you want to do is use a special view for your remote (ajax) event that just spits out the value. For example, if you want it to return JSON, you might do this:

Event Configuration:

<event-handler name="test.testFunction">
     <broadcasts>
          <message name="testFunction" />
     </broadcasts>
     <views>
          <include name="body" template="renderJson.cfm" />
     </views>
</event-handler>

Controller function:

<cffunction name="testFunction" returnType="any" output="true" >
     <cfargument name="event" type="any" required="true">
     <cfset event.setValue('justtest', 1) />
</cffunction>

renderJson.cfm:

<cfoutput>#serializeJson(event.getValue('justtest'))#</cfoutput>

If you're using Model-Glue 3, you can use the new Event Formats feature to piggy-back this ajax view on an existing event that does the same thing for a different view-format.

Upvotes: 3

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