CODEWITHSUNDEEP
pythonpython-2.7
lakshmen
lakshmen

Reputation: 29064

Printing out the output in separate lines in python

I am trying to print out the output of the maximum route each in a separate line.

The code is here:

def triangle(rows):
    PrintingList = list()
    for rownum in range (rows ):     
        PrintingList.append([])
        newValues = map(int, raw_input().strip().split())
        PrintingList[rownum] += newValues
    return PrintingList

def routes(rows,current_row=0,start=0): 
        for i,num in enumerate(rows[current_row]): 
            if abs(i-start) > 1:   
                continue
            if current_row == len(rows) - 1: 
                yield [num]
            else:
                for child in routes(rows,current_row+1,i):
                    yield [num] + child

testcases = int(raw_input())
output = []
for num in range(testcases):
    rows= int(raw_input())
    triangleinput = triangle(rows)
    max_route = max(routes(triangleinput),key=sum)
    output.append(sum(max_route))

print '\n'.join(output)

I tried this:

2
3
1
2 3
4 5 6
3
1
2 3 
4 5 6

When i try to output out the value, i get this:

print '\n'.join(output)
TypeError: sequence item 0: expected string, int found

How do change this? Need some guidance...

Upvotes: 0

Views: 7692

Answers (2)

Jon Clements
Jon Clements

Reputation: 142106

@grc is correct, but instead of creating a new string with newlines, you could simply do:

for row in output:
    print row

Upvotes: 2

grc
grc

Reputation: 23545

Try this:

print '\n'.join(map(str, output))

Python can only join strings together, so you should convert the ints to strings first. This is what the map(str, ...) part does.

Upvotes: 4

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