Reputation: 141
I'm a MS-SQL Developer, now I use this query (MySQL) ↓
SELECT A.place_idx,A.place_id,B.TODAY_CNT,C.TOTAL_CNT FROM CUSTOM_LIST
AS A
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TODAY_CNT from COUNT_TABLE where DATE(place_date) = DATE(NOW()) GROUP BY place_id)
AS B ON B.place_id=A.place_id
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TOTAL_CNT from COUNT_TABLE GROUP BY place_id)
AS C ON C.place_id=A.place_id
The result is:
I want this:
Upvotes: 9
Views: 1337
Reputation: 1916
Updated
RANK() OVER (ORDER BY TOTAL_CNT DESC DESC) AS Rank
Here I got Another Very Good Solution.:
SELECT A.place_idx,A.place_id,B.TODAY_CNT,C.TOTAL_CNT, RANK() OVER (ORDER BY TOTAL_CNT DESC) AS Rank FROM CUSTOM_LIST
AS A
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TODAY_CNT from COUNT_TABLE where DATE(place_date) = DATE(NOW()) GROUP BY place_id)
AS B ON B.place_id=A.place_id
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TOTAL_CNT from COUNT_TABLE GROUP BY place_id)
AS C ON C.place_id=A.place_id
Upvotes: -1
Reputation: 23542
Try somethink like this:
SELECT ..., C.TOTAL_CNT, (@r := @r + 1) AS rank FROM CUSTOM_LIST, (SELECT @r := 0) t
...
ORDER BY C.TOTAL_CNT DESC
Whole query:
SELECT A.place_idx,A.place_id,B.TODAY_CNT,C.TOTAL_CNT, (@r := @r + 1) AS rank
FROM CUSTOM_LIST AS A, (SELECT @r := 0) t
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TODAY_CNT from COUNT_TABLE where DATE(place_date) = DATE(NOW()) GROUP BY place_id)
AS B ON B.place_id=A.place_id
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TOTAL_CNT from COUNT_TABLE GROUP BY place_id)
AS C ON C.place_id=A.place_id
ORDER BY C.TOTAL_CNT DESC
What if we got two same values in Total_CNT?
Maybe something like this:
SELECT ..., (@last := C.TOTAL_CNT) AS TOTAL_CNT,
IF(@last = C.TOTAL_CNT, @r, @r := @r + 1) AS rank
FROM CUSTOM_LIST, (SELECT @r := 0, @last := -1) t
...
Upvotes: 4