CODEWITHSUNDEEP
c#microsoft-metrowindows-runtimemd5
Alix Bloom
Alix Bloom

Reputation: 217

WinRT md5 hashage

I try to get a md5 hash : 

        String clearKey = "test";
        IBuffer buffEntry = CryptographicBuffer.ConvertStringToBinary(clearKey, BinaryStringEncoding.Utf8);
        HashAlgorithmProvider algProvider = HashAlgorithmProvider.OpenAlgorithm(HashAlgorithmNames.Md5);

        IBuffer buffHashed = algProvider.HashData(buffEntry);

        byte[] bytesKey;
        CryptographicBuffer.CopyToByteArray(buffHashed, out bytesKey);
        Debug.WriteLine(String.Format("bytesKey lenght : {0}", bytesKey.Length));

Why my result has a size of 16 bytes? How to get a classical 32 Bytes result?

thank you for your help,

Upvotes: 0

Views: 928

Answers (1)

CodesInChaos
CodesInChaos

Reputation: 108830

MD5 has a 128 bit or 16 byte output. So it's wrong to expect 32 bytes. I assume with 32 bytes, you mean a hex encoded string, where each byte maps to two characters, resulting in a 32 character string.

In metro you can CryptographicBuffer.EncodeToHexString. to convert bytes to a hex string.

In your case this becomes:

string md5Hex = CryptographicBuffer.EncodeToHexStringbuffHashed(buffEntry);

Upvotes: 3

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