CODEWITHSUNDEEP
jenkins
user1670340
user1670340

Reputation: 159

Remove "[string]" from BUILD_LOG_REGEX extracted lines

Here is my sample string.

[echo] The SampleProject solution currently has 85% code coverage.

My desired output should be.

The SampleProject solution currently has 85% code coverage.

Btw, I had this out because I'm getting through the logs in my CI using Jenkins.

Any help? Thanks..

Upvotes: 3

Views: 3838

Answers (4)

Mohammed A Zahid
Mohammed A Zahid

Reputation: 11

Using below will remove prefix [echo] from all of your logs ,

${BUILD_LOG_REGEX, regex="^\[echo] (.*)$", maxMatches=0, showTruncatedLines=false, substText="$1"}

Upvotes: 1

fglez
fglez

Reputation: 8552

You can try substText parameter in BUILD_LOG_REGEX token to substitute the text matching your regex

New optional arg: ${BUILD_LOG_REGEX, regex, linesBefore, linesAfter, maxMatches, showTruncatedLines, substText} which allows substituting text for the matched regex. This is particularly useful when the text contains references to capture groups (i.e. $1, $2, etc.)

Upvotes: 5

C. K. Young
C. K. Young

Reputation: 223123

Andrew has the right idea, but with Perl-style regex syntaxes (which includes Java's built-in regex engine), you can do even better:

str.replaceAll("\\[.*?\\]", "");

(i.e., use the matching expression \[.*?\]. The ? specifies minimal match: so it will finish matching upon the first ] found.)

Upvotes: -2

Andrew Cooper
Andrew Cooper

Reputation: 32586

\[[^\]]*\] will match the bit you want to remove. Just use a string replace function to replace that bit with an empty string.

Upvotes: 0

Related Questions