CODEWITHSUNDEEP
php
drecute
drecute

Reputation: 758

Modify a value of a variable passed by reference

I want to be able to modify a value of a variable that is passed by reference to a function.

<?php
    function invoke($what) {
        $args = func_get_args();
        return call_user_func_array($what, $args);
    }

    function page(&$page) {
        return $page;
    }

    $page = array();
    $page['context'] = 'view';
    invoke('page', $page);
    ?>

When I call invoke(), I'm getting the warning: Parameter 1 to page() expected to be a reference, value given in invoke()

Please what am I doing wrong?

Thanks

Upvotes: 1

Views: 184

Answers (1)

NullPoiиteя
NullPoiиteя

Reputation: 57322

you are passing two value in function invoke() and getting only one use the function lke function invoke($what,$second) or just pass only one like invoke($page);

Upvotes: 2

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