CODEWITHSUNDEEP
jquery
Brained Washed
Brained Washed

Reputation: 703

How to pass variable from ajax function to another ajax function?

I want to know how to pass value from ajax function to another ajax I've tried this code but It does not work. Anyone know how to do it the right way? Thanks! 

    $("#button").click(function(){
    var passedValue = '';
    $.ajax({
        url://
        type://
        success:function(data){
            if(typeof==="object"){
            for(var i=0;i<data.length;i++){
                passedValue = data[i]["passedThis"];
            }
        }
    }
    });
    $.ajax({
        data: { receivedPassed: passedValue;}
    });
});

Upvotes: 0

Views: 2065

Answers (2)

Jo&#227;o Silva
Jo&#227;o Silva

Reputation: 91299

Chain the AJAX calls using .then(), and filter data from the first call to the second using .pipe():

$("#button").click(function() {
    $.ajax({
      url: //
      type: //
    }).pipe(function (data) {
      var passedValue = [];
      for (var i = 0; i < data.length; i++) {
        passedValue[i] = data[i]["passedThis"];
      }
      return passedValue;
    }).then(function (receivedPassed) {
      $.ajax({
        data: { receivedPassed: passedValue }
      }
    }
});

Also note that the .success() callback will be deprecated in jQuery 1.8:

Deprecation Notice: The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks will be deprecated in jQuery 1.8.

Upvotes: 1

user1675187
user1675187

Reputation:

Those requests are asynchronous, so passedValue isn't ready by the time the second one is sent. You'll probably want to send them in order:

$("#button").click(function() {
    $.ajax({
        url: //
        type: //
        success: function(data) {
            var passedValue;

            if(typeof (?) === "object") {
                for(var i = 0; i < data.length; i++) {
                    passedValue = data[i]["passedThis"];
                }

                $.ajax({
                    data: { receivedPassed: passedValue }
                });
            }
        }
    });
});

Also, you're overwriting passedValue each time through that loop. Did you mean += instead of =, or to use an array, or something?

Upvotes: 2

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