Reputation: 30749
this is a follow up from MySQL - Find rows matching all rows from joined table
Thanks to this site the query runs perfectly.
But now i had to extend the query for a search for artist and track. This has lead me to the following query:
SELECT DISTINCT`t`.`id`
FROM `trackwords` AS `tw`
INNER JOIN `wordlist` AS `wl` ON wl.id=tw.wordid
INNER JOIN `track` AS `t` ON tw.trackid=t.id
WHERE (wl.trackusecount>0) AND
(wl.word IN ('please','dont','leave','me')) AND
t.artist IN (
SELECT a.id
FROM artist as a
INNER JOIN `artistalias` AS `aa` ON aa.ref=a.id
WHERE a.name LIKE 'pink%' OR aa.name LIKE 'pink%'
)
GROUP BY tw.trackid
HAVING (COUNT(*) = 4);
The Explain for this query looks quite good i think:
+----+--------------------+-------+--------+----------------------------+---------+---------+-----------------+------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+-------+--------+----------------------------+---------+---------+-----------------+------+----------------------------------------------+
| 1 | PRIMARY | wl | range | PRIMARY,word,trackusecount | word | 767 | NULL | 4 | Using where; Using temporary; Using filesort |
| 1 | PRIMARY | tw | ref | wordid,trackid | wordid | 4 | mbdb.wl.id | 31 | |
| 1 | PRIMARY | t | eq_ref | PRIMARY | PRIMARY | 4 | mbdb.tw.trackid | 1 | Using where |
| 2 | DEPENDENT SUBQUERY | aa | ref | ref,name | ref | 4 | func | 2 | |
| 2 | DEPENDENT SUBQUERY | a | eq_ref | PRIMARY,name,namefull | PRIMARY | 4 | func | 1 | Using where |
+----+--------------------+-------+--------+----------------------------+---------+---------+-----------------+------+----------------------------------------------+
Did you see room for optimization ? Query has a runtime from around 7secs, which is to much unfortunatly. Any suggestions are welcome.
TIA
Upvotes: 3
Views: 1406
Reputation: 425593
You have two possible selective conditions here: artists's name
and the word list
.
Assuming that the words are more selective than artists:
SELECT tw.trackid
FROM (
SELECT tw.trackid
FROM wordlist AS wl
JOIN trackwords AS tw
ON tw.wordid = wl.id
WHERE wl.trackusecount > 0
AND wl.word IN ('please','dont','leave','me')
GROUP BY
tw.trackid
HAVING COUNT(*) = 4
) tw
INNER JOIN
track AS t
ON t.id = tw.trackid
AND EXISTS
(
SELECT NULL
FROM artist a
WHERE a.name LIKE 'pink%'
AND a.id = t.artist
UNION ALL
SELECT NULL
FROM artist a
JOIN artistalias aa
ON aa.ref = a.id
AND aa.name LIKE 'pink%'
WHERE a.id = t.artist
)
You need to have the following indexes for this to be efficient:
wordlist (word, trackusecount)
trackwords (wordid, trackid)
artistalias (ref, name)
Upvotes: 1
Reputation: 7459
Have you already indexed the name columns? That should speed this up.
You can also try using fulltext searching with Match and Against.
Upvotes: 0