Command line arguments passing in python

Question

Hi I am new to Python and have currently copied following script:

# filename is printer.py
import sys
for arg in sys.argv:
    print arg    # the zeroth element is the module name
raw_input("press any key")    # a trick to keep the python console open

I am trying to get the arguments followed by the module name. But running this code gives me following error:

U:\printer.py
    File "U:\printer.py", line 6
      print arg # zeroth element is the module name
              ^
SyntaxError: Invalid syntax

Does anyone know what could be wrong here? I am using Python 3.2

Answer 1

As noted by others, in python3, print is a function:

print arg

is now:

print(arg)

Also, raw_input is gone and replaced by simply input. (in py2k, input would eval the string from the commandline, but it won't do that in py3k).

---

Finally (and maybe most importantly), have you considered argparse? (untested code follows)

import argparse
parser = argparse.ArgumentParser()
parser.add_argument('foo',nargs='*',help="What a nice day we're having")
args = parser.parse_args()
print(args.foo)

Answer 2

In Python 3 print is a function:

print(arg)

Answer 3

Python 3 no longer has a print keyword, but a print function.

Try instead

print(arg)