Reputation: 37576
Is it possible to call the base Constructor at spicific point in the constructer of the subclass like:
public class SuperClass
{
public SuperClass(Object myObject)
{
// init some values ...
}
}
public class SubClass: SuperClass
{
public SubClass(): base(Object myObject)
{
//Check some preconditions
base(myObject);
// Do some other stuff
}
}
Upvotes: 2
Views: 818
Reputation: 1893
The right syntax is
public class SubClass: SuperClass
{
public SubClass(object myObject): base(myObject)
{
}
}
Here is link of using constructors. It is impossible to call it in ctor's body directly.
Upvotes: 1
Reputation: 203827
No, it's not possible.
One way to achieve this behavior you could extract the contents of the base constructor out into a method and then call that method from the subclass.
Another less closely tied method would be to just not use inheritance here. It's possible that this is a situation in which composition would make more sense. (It's impossible to say for sure without knowing more information though.)
Upvotes: 3
Reputation: 120498
No, because at //Check some preconditions
you'd have a partially constructed object. This would lead to all sorts of problems.
Upvotes: 1