Reputation: 649
start_url=requests.get('http://www.delicious.com/golisoda')
soup=BeautifulSoup(start_url)
this code is displaying the following error:
Traceback (most recent call last):
File "test2_requests.py", line 10, in <module>
soup=BeautifulSoup(start_url)
File "/usr/local/lib/python2.7/dist-packages/bs4/__init__.py", line 169, in __init__
self.builder.prepare_markup(markup, from_encoding))
File "/usr/local/lib/python2.7/dist-packages/bs4/builder/_lxml.py", line 68, in prepare_markup
dammit = UnicodeDammit(markup, try_encodings, is_html=True)
File "/usr/local/lib/python2.7/dist-packages/bs4/dammit.py", line 203, in __init__
self._detectEncoding(markup, is_html)
File "/usr/local/lib/python2.7/dist-packages/bs4/dammit.py", line 373, in _detectEncoding
xml_encoding_match = xml_encoding_re.match(xml_data)
TypeError: expected string or buffer
Upvotes: 1
Views: 2292
Reputation: 1121524
Use the .content
of the response:
start_url = requests.get('http://www.delicious.com/golisoda')
soup = BeautifulSoup(start_url.content)
Alternatively, you can use the decoded unicode text:
start_url = requests.get('http://www.delicious.com/golisoda')
soup = BeautifulSoup(start_url.text)
See the Response content section of the documentation.
Upvotes: 6
Reputation: 45644
from BeautifulSoup import BeautifulSoup
import urllib2
data=urllib2.urlopen('http://www.delicious.com/golisoda').read()
soup=BeautifulSoup(data)
Upvotes: 0
Reputation: 4085
you probebly need to Use
using
soup=BeautifulSoup(start_url.read())
or
soup=BeautifulSoup(start_url.text)
Upvotes: 0