Reputation: 303
I have this 2 lines of code which I run with R Sweave function.
\SweaveInput{samples.rnw}
\SweaveInput{\Sexpr{args$samples}}
The first line leads to the inclusion of the content of the corresponding file, while the second just causes evaluation of the Sexpr{} term but nothing else. What I want is both: first let evaluate the Sexpr{} term and afterwards do the inclusion of the respective file content.
How do solve this ? Thanks
Upvotes: 4
Views: 303
Reputation: 30114
If you use the knitr
package, the solution would be simply
<<child='samples.rnw'>>=
<<child=args$samples>>=
@
Sweave is much weaker than knitr
in terms of programmability. For example, knitr
allows the chunk options to be any valid R expressions, which is the reason why we can write child=args$samples
here; knitr
will evaluate the chunk options just like function arguments.
BTW, the child
option is equivalent to \SweaveInput{}
, but I strongly discourage the use of the pseudo LaTeX command. For more about Sweave vs knitr
, see http://yihui.name/knitr/demo/sweave/
Upvotes: 3