Reputation: 1571
I need to add spring security to my webapp. My application uses spring an also vaadin for the admin part. I'm using form-login as auth mode. So the problem I'm struggling with is that when I try to post the following form:
<form name='f' action="j_spring_security_check"
method='POST'>
<table>
<tr>
<td>User:</td>
<td><input type='text' name='j_username' value=''>
</td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='j_password' />
</td>
</tr>
<tr>
<td colspan='2'><input name="submit" type="submit"
value="submit" />
</td>
</tr>
<tr>
<td colspan='2'><input name="reset" type="reset" />
</td>
</tr>
</table>
</form>
I get a 404 redirect. So here I paste my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<context-param>
<description>Vaadin production mode</description>
<param-name>productionMode</param-name>
<param-value>false</param-value>
</context-param>
<!-- Enables Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Enables Spring internationalization -->
<filter>
<filter-name>encoding-filter</filter-name>
<filter-class>
org.springframework.web.filter.CharacterEncodingFilter
</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encoding-filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>Vaadin Application Servlet</servlet-name>
<servlet-class>com.vaadin.terminal.gwt.server.ApplicationServlet</servlet-class>
<init-param>
<description>Vaadin application class to start</description>
<param-name>application</param-name>
<param-value>com.windy.server.admin.MyVaadinApplication</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>Vaadin Application Servlet</servlet-name>
<url-pattern>/admin/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Vaadin Application Servlet</servlet-name>
<url-pattern>/VAADIN/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/views/page404.jsp</location>
</error-page>
</web-app>
and here my spring security configuration:
<security:http authentication-manager-ref="authenticatioManager" auto-config="true" pattern="/web/**">
<security:intercept-url pattern="/web/**" access="ROLE_AUTH" />
<security:form-login login-page="/loginTest.do" default-target-url="/loginWelcome.do"
authentication-failure-url="/loginfailed.do" />
<security:logout logout-success-url="/logout.do" invalidate-session="true"/>
<security:session-management>
<security:concurrency-control max-sessions="1" error-if-maximum-exceeded="true" expired-url="/web/login" />
</security:session-management>
</security:http>
<bean id="userDetailsService" class="com.ddelizia.server.service.core.impl.UserDetailsServiceImpl"/>
<security:authentication-manager id="authenticatioManager">
<security:authentication-provider user-service-ref="userDetailsService">
<!-- <security:password-encoder hash="md5"/> -->
</security:authentication-provider>
</security:authentication-manager>
I also tried to add to the form login the parameter login-processing-url="/login_spring" and changed in the form action to login_spring
my application is running on tomcat at the address localhost:8080/myapp and the login action is called on localhost:8080/myapp/login_spring but Still i get the same error.
I also tried to modify my web.xml changing the spring security filter mapping as following:
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>*.log</url-pattern>
</filter-mapping>
and changing the login-processing-url="/login_spring.log" but still I get the 404 page.
Then I tried to switch to a http-basic authentcation but in this case it works... I don't understand what I'm doing wrong...
Thanks in advance for your help
Upvotes: 0
Views: 4826
Reputation: 27995
Change your form element to:
<form name='f' action='<c:url value="/j_spring_security_check" />' method='POST'>
Also add JSTL Core taglib at the beginning of file if you don't have it:
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
EDIT:
I think I spotted source of problem. Remove pattern="/web/**"
from <http>
element leaving only <security:http authentication-manager-ref="authenticatioManager" auto-config="true">
.
What's more, j_spring_security_check
must be in springSecurityFilterChain
, so change mapping to:
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
and try now without login-processing-url
in <form-login>
but with <c:url>
. We have similar config in our Vaadin app and it works just fine.
Upvotes: 1