CODEWITHSUNDEEP
pythonlistgrep
mmann1123
mmann1123

Reputation: 5295

Remove element of a list meeting a logical condition in Python

I have filenames listed from arcpy (arcmap) as follows in 'inner'. 

inner = [u'aet1941jan.asc', u'aet2004jun.asc', u'aet1981nov.asc', u'aet1985feb.asc', u'aet1974sep.asc', u'aet1900sep.asc', u'aet1994apr.asc', u'aet1970nov.asc']

I am looking for a way to extract only the rasters that are post-1990. How can I build a logical expression that remove all elements all the old rasters from the list?

Such that the ouput would be a list:

out = [u'aet2004jun.asc', u'aet1994apr.asc']

Upvotes: 1

Views: 921

Answers (1)

Martijn Pieters
Martijn Pieters

Reputation: 1121834

A list comprehension is easiest:

out = [v for v in inputlist if int(v[3:7]) >= 1990]

Note that you cannot name a variable in; I used inputlist instead.

The above assumes characters 3 through to 6 are always the year in your values.

Upvotes: 7

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