Reputation: 3324
I need to change top-margin of an fixed div element from margin-top: 200px to margin top 0px after reaching the bottom of the page (or 200px from bottom) using vertical scrollbar.
And toggle return back if scrolling back to the top.
I guess some javascript/jQuery code code do that.
my html/layout code:
<div id="header" style="position: fixed; margin-top: 0px;">
Header content
</div>
<div id="main">
<div id="left" style="position: fixed; margin-top: 200px;">Google Ads here</div>
<div id="right">Content posts here</div>
</div>
<div id="footer">
Footer content
</div>
EDIT: Here are some images to make my question more clear.
normal state when you load the page:
problem when you scroll down, and the google ads column is in conflict with footer:
how it needs to be solved:
Upvotes: 4
Views: 9989
Reputation: 51
Derfder...
Voila, my proposed solution:
The animation's a tad jerky, but I think it does what you want
(It's my take on an earlier s/o post:
Can I keep a DIV always on the screen, but not always in a fixed position? )
Let me know what you think!
Upvotes: 2
Reputation: 5594
Hi Firstly you should have been more clearer in the first place before marking people down, as everyone give similar answers then it shows the question was not clear.
See Js Fiddle for a potential fix, please tweak as you need it with the pixels etc
Upvotes: 0
Reputation: 1898
HTML
<div id="main" style="width: 960px; margin: 0px auto;">
<div id="left" style="position: fixed; top: 200px; left: 0px; background: #000; width: 100%; color: #fff;">Google Ads here</div>
<div id="right"></div>
</div>
JAVASCRIPT
<script type="text/javascript">
$(function() {
var documentHeight = $(document).height();
var windowHeight = $(window).height();
var left = $('#left');
var leftTopPosition = $('#left').css('top');
leftTopPosition = parseInt(leftTopPosition.substring(0, leftTopPosition.length-2));
$(window).scroll(function(){
var pageOffsetY = window.pageYOffset;
if((documentHeight - pageOffsetY - windowHeight) <= 200 && leftTopPosition == 200) {
left.stop().animate({
'top': '0px'
});
leftTopPosition = 0;
}
else if((documentHeight - pageOffsetY - windowHeight) > 200 && leftTopPosition == 0) {
left.stop().animate({
'top': '200px'
});
leftTopPosition = 200;
}
});
});
</script>
Upvotes: 0
Reputation: 79850
Try below code which binds an event to window.scroll
to check if the page hits the bottom (bottom in 200px) and moves the #left
to top (margin-top: 0
)..
DEMO: http://jsfiddle.net/6Q6XY/4/ ( added some demo code to see when it hits the bottom.)
$(function() {
var $left = $('#left');
$(window).bind('scroll', function() {
if (($(document).height()
- (window.pageYOffset + window.innerHeight)) < 200) {
$left.css('marginTop', 0);
} else {
$left.css('marginTop', 200);
}
});
});
Reference: https://stackoverflow.com/a/6148937/297641
Upvotes: 1
Reputation: 13
Try this:
$(window).bind('scroll', function(){
if(($(window).height()-$(window).scrollTop())<200)
{
$('#left').css('margin-top',$(window).scrollTop());
}
else
{
$('#left').css('margin-top',200);
}
});
Upvotes: -1
Reputation: 5594
You need to implement the window scroll function, this is a jquery implementation so please ensure you include the latest jquery libaries
$(window).scroll(function () {
if ($(window).scrollTop() + $(window).height() == $(document).height()) {
//if it hits bottom
$('#left').css("margin-top", "0px");
}
else {
$('#left').css("margin-top", "200px");
}
});
Upvotes: 0
Reputation: 3626
Try somethins like this
if ($(window).scrollTop() == $(document).height() - $(window).height())
{
document.getElementById(yourid).setAttribute("style","margin-top:0px");
}
Upvotes: -1