CODEWITHSUNDEEP
php
user1683269
user1683269

Reputation: 41

how can I check a variable for a whole number value in php

If I was checking a variable to see if it was a whole number in bash the coding would be similar to 

if ! [[ "$yournumber" =~ ^[0-9]+$ ]] ; then

Is there a way in php to check if the variable contains a whole number?

Thank you all I guess I need to clarify that I want to evaluate that the number does not have a decimal value example is nuber 1 vs 1.2 or any other value with a decimal after it. Thanks in advance.

Upvotes: 2

Views: 1633

Answers (6)

lafor
lafor

Reputation: 12776

For natural numbers (non-negative whole numbers) use ctype_digit as other have suggested. For whole numbers including negatives you can use this pattern: /\-?\d+/.

Upvotes: 0

dan
dan

Reputation: 3519

There is also is_numeric(), really depends on what you want to do actually.

Upvotes: 0

Cat
Cat

Reputation: 67502

You can use ctype_digit for this:

if (ctype_digit($yournum)) {
    // ...
}

PHP Docs:

Checks if all of the characters in the provided string, text, are numerical.

This does not include ., as shown in their examples (on the page I linked).

Upvotes: 4

Jared Dickson
Jared Dickson

Reputation: 548

Perhaps this is what you're looking for?

is_int($var)

http://php.net/manual/en/function.is-int.php

Upvotes: -1

Thomas Clayson
Thomas Clayson

Reputation: 29925

You can use the function is_int() to check if a variable contains an integer (whole number)

Upvotes: 0

Niet the Dark Absol
Niet the Dark Absol

Reputation: 324620

Exactly the same way: if( preg_match("/^[0-9]+$/",$yournumber))

Alternatively, try this: if( strval(intval($yournumber)) === strval($yournumber))

Upvotes: 0

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