CODEWITHSUNDEEP
javascript
coool
coool

Reputation: 8297

javascript - shallow copy issue

I just tried something simple in javascript

name = 'velu' 
fname = name
name = 'valu'
console.log(fname) // would still print as velu...

how do you handle situation where you generated objects prototype is changed and the generated object still has a copy of the old object..

Here is the situation ...

function Cat(name){  
this.name = name  
}
var garfield = new Cat('Garfield')
Cat.prototype.greet = function(){
console.log('Meow, I am ' + this.name)
}
function Animal(){}
Cat.prototype = new Animal
Cat.prototype.constructor = Cat 
Animal.prototype.breed = function(){
console.log('Making a new animal!')
return new this.constructor()
}
 var kitty = garfield.breed() // this will not work as it garfield still is pointing to the old prototype object of Cat ...

thanks

Upvotes: 0

Views: 213

Answers (1)

Mike Christensen
Mike Christensen

Reputation: 91666

You'd have to make an object, which is passed around by reference:

var name = { Value: 'velu' };
var fname = name;
name.Value = 'valu';
console.log(fname.Value);

Upvotes: 2

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