CODEWITHSUNDEEP
octave
frankc
frankc

Reputation: 11473

In Octave, how do you source a file if the file name is stored in a variable?

I feel like this must be very easy, but I can't find the answer anywhere. In octave (and probably matlab but I haven't verified), you can source the contents of a file by doing


source /path/to/filename

However, let's say I have the filename stored in a variable called file. If you do source file, it treats file as the path rather than what is stored in file. I have tried inserting eval in various places but if that is the answer, I haven't found the correct invocation. I don't know much octave; there is surely a trivial answer to this that I am overlooking?

Upvotes: 3

Views: 896

Answers (1)

angainor
angainor

Reputation: 11810

Not sure about octave, but try to use a function call

source(fname)

That's what you do in matlab at least.

Upvotes: 2

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