CODEWITHSUNDEEP
python
atm atm
atm atm

Reputation: 69

Print statements in a for loop

I am working on a function which takes a positive integer N and computes the following sum:

1 - 2 + 3 - 4 + 5 - 6 + .... N.

My professor said we can not use "math formulas" on this, so how could I go about it?

I thought about using a for loop, but I don't know how or what to write for the print statement. This is what I have so far:

n=int(input("enter N="))
for i in range(1, n+1, 1):
    if i % 2 == 0:
        # I'm not sure what print statement to write here

I tried print(i= "+" i+1) and just weird stuff like that, but I get errors and am lost after that.

what i have now

n=int(input('enter N='))
total=0
print("sum",)
for i in range(1, n+1, 1):
    if i % 2 == 0:
        count=count - i
        print("-", i)
    else:
        count=count + i
        print("+", i, end=" ")
print("=", total)

#still get errors saying name count not defined and unsupported sperand for +:

Upvotes: 2

Views: 546

Answers (5)

abarnert
abarnert

Reputation: 366003

First, to accumulate the sum as described, and to do it by looping instead of "using math formulas", you want to do this:

n=int(input("enter N="))
total = 0
for i in range(1, n+1, 1):
    if i % 2 == 0:
        ????
    else:
        ????
print(total)

You should be able to figure out what the ???? are: you need to do something to total for each i, and it's different for even and odd.

Now, if you want it to print out something like this:

sum 1 - 2 + 3 - 4 + 5 - 6 + .... N = X

You can print things out along the way like this:

n=int(input("enter N="))
total = 0
print ("sum", end=" ")
for i in range(1, n+1, 1):
    if i % 2 == 0:
        print("-", i, end=" ")
        ????
    else:
        if i == 1:
           print(i, end=" ")
        else:
           print("+", i, end=" ")
        ????
print("=", total)

If you want to keep negative and positive totals separately and then add them, as you mentioned in an edit, change total = 0 to ntotal, ptotal = 0, 0, then change each of the ???? parts so one works on one total, one on the other.

All of the above is for Python 3. If you want to run it in Python 2, you need to turn those print function calls into print statements. For the simple cases where we use the default newline ending, that's just a matter of removing the parentheses. But when we're using the end=" ", Python 2's print statement doesn't take keyword parameters like that, so you instead have to use the "magic comma", which means to end the printout with a space instead of a newline. So, for example, instead of this:

print("+", i, end=" ")

You'd do this:

print "+", i,

Again, for Python 3, you don't have to worry about that. (Also, there are ways to make the exact same code run in both Python 2 and 3—e.g., use sys.stdout.write—which you may want to read up on if you're using both languages frequently.)

Upvotes: 2

inspectorG4dget
inspectorG4dget

Reputation: 114035

There are a lot of explanations in the answers already here. So I will try to address the different ways in which you can compute this sum:

Method 1:

def mySum(N):
    answer = 0
    for i in range(1, N+1):
        if i%2:
            answer += i
        else:
            answer -= i
    return answer

Method 2:

def mySum(N):
    answer = 0
    for i in range(1, N+1, 2):
        answer += i
    for i in range(2, N+1, 2):
        answer -= i
    return answer

Method 3:

def mySum(N):
    pos = range(1, N+1, 2)
    neg = range(2, N+1, 2)
    return sum(pos) - sum(neg)

Method 4:

def mySum(N):
    return sum([a-b for a,b in zip(range(1, N+1, 2), zip(2, N+1, 2))])

Method 5:

def mySum(N):
    return sum([i*-1 if not i%2 else i for i in range(1,N+1)])

Method 6:

def mySum(N):
    return sum(map(lambda n: n*[-1, 1][i%2], range(1, N+1)))

Again, these are only to help prime you into python. Others have provided good explanations, which this is not meant to be

Upvotes: 1

Phillip Schmidt
Phillip Schmidt

Reputation: 8818

count = 0
print "0"
for i in range(1, n+1, 1):
    if i % 2 == 0:
        count = count - i
        print "-" , i
    else:
        count = count + i
        print "+" , i
print "=", count

Upvotes: -2

John
John

Reputation: 16007

You see the difference between what happens with odd and even numbers, which is good.

So, as you cycle through the list, if the number is even, you do one operation, or else you do another operation.

After you've computed your result, then you print it.

Upvotes: 1

jonvuri
jonvuri

Reputation: 5940

You're most of the way there already. I'm not sure why you think you need to put a print statement inside the loop, though. You only want one result, right? You already have if i % 2 == 0 - which is the case where it's even - and you want to either add or subtract based on whether the current i is odd or even. So keep a running tally, add or subtract in each loop iteration as appropriate, and print the tally at the end.

Upvotes: 1

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