CODEWITHSUNDEEP
php
Ciaran
Ciaran

Reputation: 555

Generating a random image with PHP

OK, so I have a site I'm working on and need two images displayed on the page that are random. I'm running XAMPP to test it locally before it goes live. The image bank is stored in an 'images' folder in the root. The code I'm using is:

<img src="images/image<?php echo rand(1,9)); ?>.jpg" />

All my images follow the naming convention of image*n*.jpg where n is incremented through the file names. As far as I'm aware, I see no reason for this code not to generate a random image on the page. All I get is a broken link image.

EDIT: Missed the closing quotation mark for the src tag. The code does have this and it doesn't work with it.

Upvotes: 0

Views: 888

Answers (3)

rationalboss
rationalboss

Reputation: 5389

You missed the closing quotation mark for src and you have an extra closing parenthesis. Here is the corrected code:

<img src="images/image<?php echo rand(1,9); ?>.jpg" />

Upvotes: 0

Lawrence Cherone
Lawrence Cherone

Reputation: 46602

You also may want to use mt_rand() as it is more random then rand() and will give you more of a chance that the images wont be repeated.

<img src="./images/image<?=mt_rand(1,9);?>.jpg" />

If you have a broken image then view the page source and the correct path to the image.

Upvotes: 2

Rafee
Rafee

Reputation: 4078

try like this

$imagename = "image" . rand(1, 9) . ".jpg";

<img src="images/<?php echo $imagename; ?>" />

Upvotes: 0

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