CODEWITHSUNDEEP
javascriptiifeself-invoking-function
Andrei Smolensky
Andrei Smolensky

Reputation: 259

Array initialization with self-invoking function

I'm trying to initialize an array with self-invoking function, assume for simplicity as an example, that initial values are squares of numbers from 0 to 4. The new keyword creates new object, so one can access fields of newly created object with this.x or this[x] inside the IIFE body, following the new keyword. The code is:

var arr = new (function() {
    for (var i=0; i<5; i++) { this[i]=i*i; }
})();

Now, you can access corresponding fields of variable arr like arr[4], and get 16. That's perfectly fine if you only work with arr like with an object, but once you try to treat it like an array, you have a problem. Namely, you can't apply functions like reduce to it:

< arr.reduce(...);
> TypeError: arr.reduce is not a function

That's because arr is really an object, not an array:

< arr;
> ({0:0, 1:1, 2:4, 3:9, 4:16})

So here is my question: how to avoid such behavior within this method? How to make JavaScript interpret this newly created object as an array?

Upvotes: 2

Views: 2514

Answers (2)

Bergi
Bergi

Reputation: 665456

Without the IEFE it is shorter and more clear:

var arr = [];
for (var i=0; i<5; i++) arr[i] = i*i;

Without the additional counter variable i, you could do:

for (var arr=[]; arr.length<5; ) arr[arr.length] = Math.pow(arr.length, 2);

Upvotes: 3

6502
6502

Reputation: 114579

You don't need to use the new keyword for that...

var arr = (function() {
               var x = [];
               for (var i=0; i<4; i++)
                   x.push(i*i);
               return x;
           })();

the new keyword creates an object and sets its constructor, then binds this to it and calls the function. You don't need anything of that except calling the function, so just do so.

Upvotes: 3

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