Reputation: 18273
How to find the n-th weekday of a month based on @ref_date
, @n
, and @week_day
in MySQL:
SET @ref_date = '2012-09-25';
SET @n = 3; #The third week
SET @week_day = 0; #Monday
The result should be: 2012-09-17
.
Any suggestion appreciated.
Upvotes: 1
Views: 2257
Reputation: 35533
You have @weekday
using the standard '0 == Monday', but MySql uses a 1-based standard with '1 == Sunday'. Assuming we are constrained to say that 0 must equal Monday, you can do this:
SET @first_day = DATE_SUB(@ref_date, INTERVAL DAYOFMONTH(@ref_date) - 1 DAY);
SET @first_day_of_week = (DAYOFWEEK(@first_day) - 2) % 7;
SET @solution = DATE_SUB(DATE_ADD(@first_day, INTERVAL @n WEEK), INTERVAL ( 7 - ((@week_day - @first_day_of_week + 7) % 7) ) DAY);
So as a single query that would be:
SELECT DATE_SUB( DATE_ADD( DATE_SUB( @ref_date, INTERVAL DAYOFMONTH(@ref_date) - 1 DAY), INTERVAL @n WEEK), INTERVAL ( 7 - ((@week_day - ((DAYOFWEEK(DATE_SUB( @ref_date, INTERVAL DAYOFMONTH(@ref_date) - 1 DAY)) - 2) % 7) + 7) % 7) ) DAY);
Upvotes: 3
Reputation: 54016
find in one of the solution in SO here
SELECT WEEK(dateField, 5) -
WEEK(DATE_SUB(dateField, INTERVAL DAYOFMONTH(dateField) - 1 DAY), 5) + 1
Read Week of the Month in Mysql
Upvotes: 1