Reputation: 235
I have the latest codeigniter version, and was wondering how can i get the segments in a url by their parameter name. For instance, here is a sample url:
www.somewebsitedomain.com/param1=something/param2=somethingelse/
now lets say i want to get the value for 'param1', which is 'something', how would i do so using the uri class?
Because by default the uri class only gets segments by number, or the order in which they appear, but i want to get segments by the parameter name in that segment. Or in general just get the parameter value. Hope that makes sense...
Upvotes: 1
Views: 4695
Reputation: 162
I'm not sure this is what you're asking, but in many applications, URLs follow the form www.domain.com/controller/method/key1/value1/key2/value2. So I decided to extend the CI_URI class to return the value of any "key".
If you put this in your application/core folder, in a file named, MY_URI.php, it extends the built-in URI class:
class MY_URI extends CI_URI {
/* call parent constructor */
function __construct() {
parent::__construct();
}
/* return value of the URI segment
which immediately follows the named segment */
function getNamed($str=NULL) {
$key = array_search($str, $this->segments);
if ($key && isset($this->segments[$key+1])) {
return $this->segments[$key+1];
}
return false;
}
}
Then if your URLs are in the form
www.somewebsitedomain.com/param1/something/param2/somethingelse/
you can call this function as follows:
$this->uri->getNamed('param1)
- returns "something"
$this->uri->getNamed('param2)
- returns "somethingelse"
Upvotes: 0
Reputation: 1683
You could actually put them as GET vars and use the Input Class:
$param = $this->input->get('param1'); // something
or you can do:
$params = $this->input->get(); // array('param1' => 'something', 'param2' => 'somethingelse')
to get all the parameters
Upvotes: 1
Reputation: 355
You could do $this->uri->uri_to_assoc(n)
which will give something like the following
[array]
(
'name' => 'joe'
'location' => 'UK'
'gender' => 'male'
)
Then just just the param name you would like.
Source: http://codeigniter.com/user_guide/libraries/uri.html
Upvotes: 3