Reputation: 21
Is the first element of arr1
getting added?
cout
is giving me an error. What am I doing wrong?
#include <iostream>
using std::cin; using std::cout; using std::endl;
#include <string>
using std::string;
#include <vector>
using std::vector;
#include <cstddef>
using std::size_t;
int main ()
{
vector <int> ivec1; //defines a vector named ivec1 to hold values not yet defined
int arr1 [5] = {10, 20, 30 , 40, 50}; // defines array named arr1 with 5 values
ivec1.push_back (arr1 [0]);
cout << ivec1 << endl;
return 0;
}
Upvotes: 1
Views: 141
Reputation: 59831
The answer is quite simple: The operation you are invoking is simply not defined. The IO stream library is blissfully unaware of C++ standard library containers (besides std::string
) and does not know how to print them. You will need to do that yourself.
std::vector<int> v;
for(auto& x : v)
std::cout << v << " "; // print each element
std::cout << std::endl; // and a linebreak
Upvotes: 1
Reputation: 921
I guess cout is not able to work with vectors. I'd implement something like this (I'm sorry for my C++ I didn't write in C++ since 2006...
#include "stdafx.h"
#include <iostream>
using std::cin; using std::cout; using std::endl;
#include <string>
using std::string;
#include <vector>
using std::vector;
#include <cstddef>
using std::size_t;
void fillVector(int output[], vector<int>& input, int size)
{
for(int i=0;i<size; i++)
{
input.push_back(output[i]);
}
}
void printVector(vector<int>& input)
{
for(int i=0; i<input.size(); i++)
{
cout << input.at(i);
if(i!=input.size()-1)
{
cout << ",";
}
}
cout << endl;
}
int main ()
{
vector <int> ivec1; //defines a vector named ivec1 to hold values not yet defined
int arr1 [5] = {10, 20, 30 , 40, 50}; // defines array named arr1 with 5 values
int sz = sizeof(arr1) / sizeof(int);
fillVector(arr1, ivec1, sz);
printVector(ivec1);
return 0;
}
Upvotes: 0