Reputation: 4100
I have an Array[Any]
from Java JPA containing (two in this case, but consider any a small number of) differently-typed things. I would like to represent these as tuples instead.
I have some quick and dirty conversion code, and wondered how it could be improved and perhaps made more generic.
val pair = query.getSingleOrNone // returns Option[Any] (actually a Java array)
pair collect { case array: Array[Any] =>
(array(0).asInstanceOf[MyClass1], array(1).asInstanceOf[MyClass2]) }
Upvotes: 29
Views: 41843
Reputation: 678
You can use Tuple.fromArray. Works for Scala 3.0.2, haven't checked earlier versions.
scala> val a = Array("a", "b")
val a: Array[String] = Array(a, b)
scala> Tuple.fromArray(a)
val res1: Tuple = (a,b)
Upvotes: 5
Reputation: 904
Use map { case Array(f1,f2) => (f1,f2) }
.
Here is an example:
Array( "CA:California", "WA:Washington", "OR:Oregon").
map(s => s.split(":")).
map { case Array(f1,f2) => (f1,f2)}
Upvotes: 25
Reputation: 155
My solution is as below:
val loginValues = line.split(",") // return an Array
val (ip, date, action, username) = (loginValues(0), loginValues(1).toLong, loginValues(2), loginValues(3))
Upvotes: 13
Reputation: 62835
How about this?
val pair = query.getSingleOrNone
pair collect { case Array(x: MyClass1, y: MyClass2, _*) => (x,y) }
// result would be Option[(MyClass1, MyClass2)]
Upvotes: 38