CODEWITHSUNDEEP
bashshellsed
Nico varium
Nico varium

Reputation: 41

extract subtring, splitting at pattern, using sed in bash script

Solution:

#!/bin/bash
for f in *.mp3; do
    d="${f% - *}"
    if [ -d $d ]; then
        mv "$f" "$d/";
    else 
        mkdir "$d" && mv "$f" "$d/";
    fi 
done

I'm trying this:

$ echo "foo - bar.ext" | sed 's/\('" - "'\).*/\1/' | sed 's/ - //'

which gives me just "foo". I guess there is a better way...Don't hit me hard, I'm new to sed. But now, how to include it in a loop like this:

#!/bin/bash
for f in *.ext; do
    d="${f%.*}"
    #Extract Filename String before the " - " and write back to $d
    mkdir "$d" && mv "$f" "$d/";
done

Thanks in advance

Further information:

$f shall remain unchanged while a directory name, stored in $d, shall contain only the "foo"- part of a pattern matching "foo - bar.ext".

Basically, a list of files, following the pattern "foo - bar.ext" should be moved to directories which are named "foo".

E.g.: foo1 - bar1.ext foo1 - bar2.ext foo1 - bar2.ext --> will be moved to subdir "foo1"

anotherfoo - anotherbar.ext --> will be moved to subdir "anotherfoo"

Upvotes: 2

Views: 437

Answers (1)

nosid
nosid

Reputation: 50124

You have it almost already. Only a three characters are missing in your code fragment.

#!/bin/bash
for f in *.ext; do
    d="${f% - *}"
    mkdir "$d" && mv "$f" "$d/";
done

Upvotes: 1

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