CODEWITHSUNDEEP
javacastingintlong-integer
user1698804
user1698804

Reputation: 1

Java: Found long, required int

I'm trying to sort some arrays in Java using this line:

a = sortFacade.sort(2, false, a);

where 'a' is an already initialised int array. When I try to compile it, I'm told that the 2 is a long, not an int. I've tried casting it with (int)2 with no luck.

I also tried the line

sortFacade.sort(2, false, a);

and the code compiles.

does anyone know a fix to this?

Edit: Here's the message I get in Terminal:

Experimenter.java:146: incompatible types
found   : long
required: int[]
        a = sortFacade.sort(2, false, a);
                           ^

This line is found in code like this:

public static void Experiment1()
{
   for(int size = 5000; size <= 100000; size = size + 5000)
   {
     int[] a randomArray(size, 1000); //a random array of size 'size' and values from 1 - 1000
     a = sortFacade.sort(2, false, a);
     /** This is where the error occurs. 2 specifies insertion sort (error occurs 
      with other acceptable numbers here as well,false specifies descending
      order, 'a' specifies the array to be sorted.*/
   }
}

The SortFacade is a facade that interacts with all my different sorting algorithms. 2 is an acceptable value and calls to the same method (with different parameters) do work in other parts of the code.

Upvotes: 0

Views: 2112

Answers (2)

Raul Rene
Raul Rene

Reputation: 10290

This basically talks for itself.

Experimenter.java:146: incompatible types
found   : long
required: int[]

You said yourself that the variable a is an array of integers. The above error tells you that although the method returns a long, you require it to return an array of integers int[], because you try to assign that long value to a.

Upvotes: 1

jcern
jcern

Reputation: 7848

if a is an int[] array, then it would seem that the error you are receiving is because sortFacade.sort has a return type of long and you are trying to assign it to the a array - which is illegal.

The reason sortFacade.sort(2, false, a); compiles is because you are not assigning it to anything. If you said: long b = sortFacade.sort(2, false, a); it should compile and work.

Upvotes: 0

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