CODEWITHSUNDEEP
xsltxslt-2.0
Joe Foley
Joe Foley

Reputation: 168

Parameter value not being passed in xslt call-template

Fairly new to XSLT and saw the with-param as a way to get something done.

        <xsl:variable name="PQB_ID">
         <!-- <xsl:value-of select="wd:SSN"/> -->
           <xsl:value-of>123</xsl:value-of>
         </xsl:variable>

         <xsl:call-template name="testing">
                 <xsl:with-param name="PQB_ID"></xsl:with-param>
         </xsl:call-template>

And my template name is below:

<xsl:template name="testing">
   <xsl:param name="PQB_ID"></xsl:param>
   <xsl:value-of select="$PQB_ID"></xsl:value-of>
</xsl:template>

At a minimum, I would expect to see 123. Or, when my <xsl:value-of select="wd:SSN"/> is uncommented, I would expect to see the value in my program. As it is, I get nothing back.

What am I missing?

Upvotes: 1

Views: 2064

Answers (2)

Michael Kay
Michael Kay

Reputation: 163595

Note also, it's a really good idea in XSLT 2.0 to declare the type of the expected parameter in xsl:param. Are you expecting a string? an integer? I don't expect you are expecting a document node, which is what you are carefully creating with the code 

 <xsl:variable name="PQB_ID">
   <xsl:value-of>123</xsl:value-of>
 </xsl:variable>

If the template wants an integer, then you don't need a whole new document to contain it; just write

<xsl:variable name="PQB_ID" select="123"/>

Upvotes: 0

Ian Roberts
Ian Roberts

Reputation: 122414

<xsl:with-param name="PQB_ID"></xsl:with-param>

will pass an empty value for the parameter. If you want to pass through the value of the global PQB_ID variable, you need to do so explicitly

 <xsl:with-param name="PQB_ID" select="$PQB_ID"/>

Upvotes: 6

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