user1629366
user1629366

Reputation: 2011

compare two variables in jinja2 template

Given I have two variables {{ profile }} with a value "test" and {{ element.author }} again with the value "test". In jinja2 when I try to compare them using an if, nothing shows up. I do the comparison as follows:

{% if profile == element.author %}
{{ profile }} and {{ element.author }} are same
{% else %}
{{ profile }} and {{ element.author }} are **not** same
{% endif %}

I get the output test and test are not same Whats wrong, how can I compare?

Upvotes: 18

Views: 73925

Answers (4)

Thomas Gak-Deluen
Thomas Gak-Deluen

Reputation: 2941

I have the same problem, two variables having an integer value do not equal the same when they are the same value.

Is there any way to make this work in any way. Also tried to use str() == str() or int() == int() but there is always an undefined error.

UPDATE

Found Solution: Simply use filters such as {{ var|string() }} or {{ var|int() }} https://stackoverflow.com/a/19993378/1232796

Reading the doc it can be found here https://jinja.palletsprojects.com/en/3.1.x/templates/#builtin-filters

In your case you would want to do

{% if profile|string() == element.author|string() %}
{{ profile }} and {{ element.author }} are same
{% else %}
{{ profile }} and {{ element.author }} are **not** same
{% endif %}

Upvotes: 26

peter-sari
peter-sari

Reputation: 57

I would suggest using the |lower filter:

{% if profile|lower == element.author|lower %}

That doesn't only cast the variables to the same string type, but also helps avoid mismatch coming from the different ways names might be typed.

Upvotes: 0

mazzi
mazzi

Reputation: 86

You can check the types of the variables using one of the many built in tests that jinja2 has available. For instance string() or number(). I had the same problem and I realized that was the types.

Upvotes: 1

maddyblue
maddyblue

Reputation: 16882

profile and element.author are not the same type, or otherwise aren't equal. However, they do happen to output the same value when converted to a string. You need to correctly compare them or change their types to be the same.

Upvotes: 2

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