CODEWITHSUNDEEP
springspring-mvcservlet-dispatching
cometta
cometta

Reputation: 35739

No mapping found for HTTP request with URI [/WEB-INF/pages/apiForm.jsp]

My handler forwards to internalresourceview 'apiForm' but then i get error 404 RequestURI=/WEB-INF/pages/apiForm.jsp. I'm sure apiForm.jsp located in /WEB-INF/pages/

13:45:02,034 DEBUG [org.springframework.web.servlet.view.JstlView] - Forwarding to resource [/WEB-INF/pages/apiForm.jsp] in InternalResourceView 'apiForm'
13:45:02,035 DEBUG [org.springframework.web.servlet.DispatcherServlet] - DispatcherServlet with name 'testapp2' determining Last-Modified value for [/WEB-INF/pages/apiForm.jsp]
13:45:02,038 DEBUG [org.springframework.web.servlet.DispatcherServlet] - No handler found in getLastModified
13:45:02,038 DEBUG [org.springframework.web.servlet.DispatcherServlet] - DispatcherServlet with name 'testapp2' processing request for [/WEB-INF/pages/apiForm.jsp]
13:45:02,038 WARN [org.springframework.web.servlet.PageNotFound] - No mapping found for HTTP request with URI [/WEB-INF/pages/apiForm.jsp] in DispatcherServlet with name 'testapp2'
13:45:02,045 DEBUG [org.springframework.web.servlet.DispatcherServlet] - Successfully completed request
13:45:02,048 DEBUG [org.springframework.web.servlet.DispatcherServlet] - Successfully completed request

this is how my dispatcher.xml look like..

<bean id="viewResolver"
    class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
    <property name="prefix" value="/WEB-INF/pages/"/>
    <property name="suffix" value=".jsp"/>
</bean>

Upvotes: 93

Views: 432429

Answers (16)

Brad Parks
Brad Parks

Reputation: 72293

This could also happen when your app doesn't actually compile, yet it's still launched in Tomcat. When I saw this happen, it wasn't compiling because the project had a "project specific" JDK specified, and the code was checked out on a machine that didn't have that specific JDK. Eclipse defaulted to a JRE instead, not a JDK, and then the app wasn't compiled.

To fix it in our specific case, we just turned off "Project Specific Settings" here:

"Project | Properties | Java Compiler"

Here's more detailed info on how to do this: https://stackoverflow.com/a/2540730/26510

Upvotes: 2

Junchen Liu
Junchen Liu

Reputation: 5634

you will get a No mapping found for HTTP request with URI error

if you scanned the wrong package

e.g your controller is in my.package.abc but you mistakenly put

<context:component-scan base-package="my.package.efg*" />

or

@ComponentScan("my.package.efg*")

which in the sense, your controller doesn't get scanned into the web application context, when request comes in not just url, but the entire class is not found!

Upvotes: 13

Vahid Hassani
Vahid Hassani

Reputation: 674

I had the same problem, Of course there was a little difference. The story was that when I was removing the below line:

<mvc:resources mapping="/resources/**" location="classpath:/resources/" />

Everything was OK but in presence of that line the same error raise.

After some trial and error I found I have to add the below line to my spring application context file:

<mvc:annotation-driven />

Hope it helps!

Upvotes: 3

Evald
Evald

Reputation: 122

I have encountered this problem in Eclipse Luna EE. My solution was simply restart eclipse and it magically started loading servlet properly.

Upvotes: 1

motoprog
motoprog

Reputation: 186

I think I read the entire internet to figure out how to get sitemesh to handle my html paths without extension + API paths without extension. I was wrapped up in a straight jacket figuring this out, every turn seemed to break something else. Then I finally came upon this post.

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet>
    <servlet-name>jsp</servlet-name>
    <servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>jsp</servlet-name>
    <url-pattern>/WEB-INF/views/*</url-pattern>
 </servlet-mapping>

<servlet-mapping>
    <servlet-name>jsp</servlet-name>
    <url-pattern>/WEB-INF/decorators/*</url-pattern>
</servlet-mapping>

Enter this in your dispatcher-servlet.xml

<mvc:default-servlet-handler/>

Upvotes: 9

Chem
Chem

Reputation: 89

With Spring 3.1 and Tomcat 7 I got next error:

org.springframework.web.servlet.DispatcherServlet noHandlerFound No mapping found for HTTP request with URI [/baremvc/] in DispatcherServlet with name 'appServlet'

And I needed to add to web.xml next configuration:

<welcome-file-list>
    <welcome-file/>
</welcome-file-list>

And the application worked!

Upvotes: 8

Tarnveer Kaur
Tarnveer Kaur

Reputation: 61

"/openStudentPage" is the page that i want to open first, i did :

 @RequestMapping(value = "/", method = RequestMethod.GET)
    public String index(Model model) {
     return "redirect:/openStudentPage";
    }

@RequestMapping(value = "/openStudentPage", method = RequestMethod.GET)
public String listStudents(Model model) {
    model.addAttribute("student", new Student());
    model.addAttribute("listStudents", this.StudentService.listStudents());
    return "index";
}

Upvotes: 0

Karthik N G
Karthik N G

Reputation: 2331

Simple check can be made. I am currently using Spring MVC architecture along with hibernate. I had missed writing @Controller annotations just above class name. This was causing the problem for me.

@Controller
public class MyClass{
    ...
}

Hope this simple check solves your problem.

Upvotes: 8

James Jithin
James Jithin

Reputation: 10555

Just add <mvc:default-servlet-handler /> to your DispatcherServlet configuration and you are done!

Upvotes: 19

Ashok
Ashok

Reputation: 1

change the your servlet name dispatcher to any other name .because dispatcher is predefined name for spring3,spring4 versions.

<servlet>
    <servlet-name>ahok</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>ashok</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

Upvotes: -4

AlexZam
AlexZam

Reputation: 1196

Solution that helped me is: do not map DispatcherServlet to /*, map it to /. Final config is then:

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        ...
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

Upvotes: 9

demongolem
demongolem

Reputation: 9718

Unfortunately, this is a rather broad class error message. Yet another thing which could be going wrong is if you are missing some classes/jars. For example, if you are missing the spring-expression jar file, the dispatch-servlet is not going to be able to locate your controller no matter how hard you try and how correct everything else is configured.

Upvotes: 1

Mr Baloon
Mr Baloon

Reputation: 2776

Same answer as Brad Parks... more text though

I had the exact same problem and tried the above solutions along with many others, all with negative results. I even started out with a new, fresh Dev env and simply installed a spring-mvc-template and tried to run it directly after install (should work, but failed for me)

For me the problem was that I was using jdk1.6 in my project, but my selected execution environment in eclipse was jdk1.7. The solution was to change the project specific execution environment settings so that this project is set to jdk1.6. Right click project --> Properties --> Java Compiler --> Check "Enable project specific settings" if it's not already checked --> select the appropriate jdk (or add if it's not installed).

I hope this can help someone and save that persons time, because I have spent the last few days looking for the answer on every corner of the Internet. I accidently stumbled upon it myself when I started to get desperate and look for the solution in areas where it (according to my brain) was less likely to be found. =)

My 2 cents. Thanks!

Edit1: Use project specific settings

Edit2: Just realized Brad Parks already answered this in this very thread. Well, at least I got the "Editor"-badge out of this one =D

Upvotes: 2

sourcedelica
sourcedelica

Reputation: 24047

Yes, I know I'm late to this party but it might help others.

The servlet container chooses the mapping based on the longest path that matches. So you can put this mapping in for your JSPs and it will be chosen over the /* mapping.

<servlet-mapping>
  <servlet-name>jsp</servlet-name>
  <url-pattern>/WEB-INF/pages/*</url-pattern>
 </servlet-mapping>

Actually for Tomcat that's all you'll need since jsp is a servlet that exists out of the box. For other containers you either need to find out the name of the JSP servlet or add a servlet definition like:

<servlet>
  <servlet-name>jsp</servlet-name>
  <servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
</servlet>

Upvotes: 90

NA.
NA.

Reputation: 6589

What you need is to have a controller that responds to the url first which then renders your jsp. See this link for a solution.

Upvotes: 0

ptomli
ptomli

Reputation: 11818

Looks like DispatcherServlet is trying to process the request for apiForm.jsp, which suggests to me that your web.xml servlet-mapping is directing requests for that space to DispatcherServlet.

You might have something like this?

<servlet-mapping>
  <servlet>dispatcher</servlet>
  <url-pattern>/*</url-pattern>
</servlet-mapping>

Try calling your controllers with a different extension (.do for example) and update the servlet-mapping to suit

 <servlet-mapping>
  <servlet>dispatcher</servlet>
  <url-pattern>*.do</url-pattern>
</servlet-mapping>

Upvotes: 155

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