CODEWITHSUNDEEP
java
Lavinia
Lavinia

Reputation: 263

printf %f with 4 decimals and the symbol "%" in the end

I have a vector:

p[0]=0.40816269
p[1]=0.37576407
p[2]=0.16324950
p[3]=0.05282373

I need to print the values of the vector as percentage with 4 decimals. I tried:

for(int i=0; i<p.length;i++)
{
    System.out.printf("Criterion "+i+" has the weigth=%.4f \n" , p[i]*100);
}

which gives me:

Criterion 0 has the weigth=40.8163, .....

but I want to print:

Criterion 0 has the weigth=40.8163 %, .....

I cannot add the symbol "%" in the end of each row. If I try:

System.out.printf("Criterion "+i+" has the weigth=%.4f %\n" , p[i]*100);

or:

System.out.printf("Criterion "+i+" has the weigth=%.4f "+"%\n" , p[i]*100);

program throws an exception. Thank you in advance!

Upvotes: 2

Views: 941

Answers (5)

Jason Sperske
Jason Sperske

Reputation: 30436

Why not just do this:

System.out.printf("Criterion %d has the weigth=%.4f%%\n", i, p[i]*100)

If you are going to use printf, then use it all the way :)

Upvotes: 2

Bhesh Gurung
Bhesh Gurung

Reputation: 51030

"Criterion "+i+" has the weigth=%.4f %%\n" just add a %%.

Upvotes: 1

fvu
fvu

Reputation: 32973

As the others said, but why not

System.out.printf("Criterion %d has the weight=%.4f%%\n" , i, p[i]*100);

It's a bit odd to use printf to format the float, but not for i..

Upvotes: 1

nneonneo
nneonneo

Reputation: 179552

Use %% to print out a percent sign:

System.out.printf("Criterion "+i+" has the weight=%.4f%%\n" , p[i]*100);

Upvotes: 2

Jon Lin
Jon Lin

Reputation: 143906

You need to escapee the % with %%:

System.out.printf("Criterion "+i+" has the weigth=%.4f %%\n" , p[i]*100);

For more information, see the java.util.Formatter conversions spec

Upvotes: 5

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