CODEWITHSUNDEEP
javaweb-servicesjakarta-eesoap
membersound
membersound

Reputation: 86935

Catching any webservice exception?

I have a soap @webservice, and a client sending requests as below:

try {
  // any webservice confniguration here
  webservice.call();
} catch (Exception e) {
  System.out.println("ERROR");
}

Now if the connections time out, I'm getting a java.net.socketTimtoutException with stacktrace, plus my error sysouts above. How can I prevent the stacktrace from being printed to console? I don't understand why I ever get it as I'm catching any occuring exception, aren't I?

Upvotes: 3

Views: 935

Answers (1)

GingerHead
GingerHead

Reputation: 8240

Then it's clearly obvious that somewhere in between, a try/catch block catches the exception, prints the stack trace, and then rethrows it. As @WernerVesterås said.
I can advise you to debug the code.

Upvotes: 1

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