CODEWITHSUNDEEP
c#
Wesley Skeen
Wesley Skeen

Reputation: 8285

Dividing by a higher number returning 0

When I try to do this

double test = ((2 / 7) * 100);

it returns 0.

Does anybody know why this is and how to work around it?

Thanks

Upvotes: 0

Views: 1778

Answers (6)

sergeyG
sergeyG

Reputation: 54

It's because of division. A division of two int numbers returns int number truncating any decimal points. Hence the result of the operation 2/7 will be 0.

It should be something like this:

double test = ((2.0 / 7.0) * 100.0);

Upvotes: 0

Guffa
Guffa

Reputation: 700152

You are doing integer math, and only converting to double when you have the final result.

2 / 7 = 0

while

2.0 / 7.0 = 0.285714285714285

Do the math with double values:

double test = ((2.0 / 7.0) * 100.0);

Upvotes: 0

Matthew Watson
Matthew Watson

Reputation: 109537

It's doing integer division because all the operands are integers.

To fix it, change at least one the operands to doubles like this:

double test = ((2.0 / 7.0) * 100.0);

Upvotes: 0

Achim
Achim

Reputation: 15692

You are dividing integers, so 2 / 7 becomes already 0. Just try 2.0 / 7.0 and you'll get the correct result.

Upvotes: 0

SLaks
SLaks

Reputation: 887195

You're dividing integers.

If you want a non-integer result, at least one operand must be a float or double (or decimal).

You can do that by adding .00 to any of the literals to create a literal.

Upvotes: 5

Kuba
Kuba

Reputation: 3056

2 / 7 is integer division, and will return 0. Try this instead

2.0 / 7

(double) 2 / 7

Upvotes: 13

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