Reputation: 3265
I'm trying to add header for my request using HttpUrlConnection
but the method setRequestProperty()
doesn't seem working. The server side doesn't receive any request with my header.
HttpURLConnection hc;
try {
String authorization = "";
URL address = new URL(url);
hc = (HttpURLConnection) address.openConnection();
hc.setDoOutput(true);
hc.setDoInput(true);
hc.setUseCaches(false);
if (username != null && password != null) {
authorization = username + ":" + password;
}
if (authorization != null) {
byte[] encodedBytes;
encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + encodedBytes;
hc.setRequestProperty("Authorization", authorization);
}
Upvotes: 315
Views: 534740
Reputation: 61
if you are sure that the server is trustworthy and you are only connecting to it for testing purposes, you can use this option.
You will need to modify your Java code to use a custom TrustManager that does not validate the server's certificate.
additional code snippet for json body. And also send request and get repsponse examples:
//Create json body
// option1
JSONObject json = new JSONObject();
json.put("param1Name", param1);
json.put("param2Name", param2);
//Create json body
// option2
//String jsonInputString = "{"param1Name": param1, "param2Name": param2}";
String jsonInputString = json.toJSONString();
//Create the Request Body
try(OutputStream os = myURLConnection.getOutputStream()) {
byte[] input = jsonInputString.getBytes("utf-8");
os.write(input, 0, input.length);
}
//Read the Response From Input Stream
try(BufferedReader br = new BufferedReader(
new InputStreamReader(myURLConnection.getInputStream(), "utf-8"))) {
String responseLine = null;
while ((responseLine = br.readLine()) != null) {
response.append(responseLine.trim());
}
System.out.println(response.toString());
}
Here is an full example of such a code is here
Upvotes: 0
Reputation: 71
It work for me. I had to send request to another hand, and transfer header "Authorization" + jwt and some params via POST. By another side we formed jettyRequest with params and headers. If I send this sequence of code:
URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
// some code add params
then I received only params in a body. If I send this:
URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
myURLConnection.setRequestMethod("POST");
// some code add params
then I received headers Authorization and params.
Upvotes: 0
Reputation: 1248
Finally this worked for me
private String buildBasicAuthorizationString(String username, String password) {
String credentials = username + ":" + password;
return "Basic " + new String(Base64.encode(credentials.getBytes(), Base64.NO_WRAP));
}
Upvotes: 6
Reputation: 5292
I have used the following code in the past and it had worked with basic authentication enabled in TomCat:
URL myURL = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)myURL.openConnection();
String userCredentials = "username:password";
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userCredentials.getBytes()));
myURLConnection.setRequestProperty ("Authorization", basicAuth);
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
myURLConnection.setRequestProperty("Content-Length", "" + postData.getBytes().length);
myURLConnection.setRequestProperty("Content-Language", "en-US");
myURLConnection.setUseCaches(false);
myURLConnection.setDoInput(true);
myURLConnection.setDoOutput(true);
You can try the above code. The code above is for POST, and you can modify it for GET
Upvotes: 515
Reputation: 161
If you are using Java 8, use the code below.
URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;
String basicAuth = Base64.getEncoder().encodeToString((username+":"+password).getBytes(StandardCharsets.UTF_8));
httpConn.setRequestProperty ("Authorization", "Basic "+basicAuth);
Upvotes: 15
Reputation: 210
Just cause I don't see this bit of information in the answers above, the reason the code snippet originally posted doesn't work correctly is because the encodedBytes
variable is a byte[]
and not a String
value. If you pass the byte[]
to a new String()
as below, the code snippet works perfectly.
encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + new String(encodedBytes);
Upvotes: 20
Reputation: 2248
With RestAssurd you can also do the following:
String path = baseApiUrl; //This is the base url of the API tested
URL url = new URL(path);
given(). //Rest Assured syntax
contentType("application/json"). //API content type
given().header("headerName", "headerValue"). //Some API contains headers to run with the API
when().
get(url).
then().
statusCode(200); //Assert that the response is 200 - OK
Upvotes: 1
Reputation: 331
Your code is fine.You can also use the same thing in this way.
public static String getResponseFromJsonURL(String url) {
String jsonResponse = null;
if (CommonUtility.isNotEmpty(url)) {
try {
/************** For getting response from HTTP URL start ***************/
URL object = new URL(url);
HttpURLConnection connection = (HttpURLConnection) object
.openConnection();
// int timeOut = connection.getReadTimeout();
connection.setReadTimeout(60 * 1000);
connection.setConnectTimeout(60 * 1000);
String authorization="xyz:xyz$123";
String encodedAuth="Basic "+Base64.encode(authorization.getBytes());
connection.setRequestProperty("Authorization", encodedAuth);
int responseCode = connection.getResponseCode();
//String responseMsg = connection.getResponseMessage();
if (responseCode == 200) {
InputStream inputStr = connection.getInputStream();
String encoding = connection.getContentEncoding() == null ? "UTF-8"
: connection.getContentEncoding();
jsonResponse = IOUtils.toString(inputStr, encoding);
/************** For getting response from HTTP URL end ***************/
}
} catch (Exception e) {
e.printStackTrace();
}
}
return jsonResponse;
}
Its Return response code 200 if authorizationis success
Upvotes: 5