CODEWITHSUNDEEP
pythonbashpexpect
andybandy12
andybandy12

Reputation: 79

pexpect need to use pipe without starting the bash shell since the bash shell does not understand the command

I want to do something likethis using pexpect

echild = pexpect.spawn('/bin/bash -c "sysinfo -v | grep "SCM"')
fout = file('/home/kiva/release_file.txt' , 'w+')
child.logfile = fout

The problem is that I want the out of that command into a textfile but I have to start a shell since we cannot use pipe in spawn(). The bash shell does not understand sysinfo -v and complains about it.

Do you guys have any idea or know of a way in which I can get the desired output into the file without opening the bash terminal? I can solve the issue by just using the spawn() method without grepping it but I want the exact match and hence grep is necessary.

Thank you

Upvotes: 0

Views: 817

Answers (1)

Catalin Luta
Catalin Luta

Reputation: 771

From your short example I do not see why you specifically need to use pexpect to achieve this. I would go for the Popenway. Here's a link that might prove useful:

Replacing shell pipeline - Popen

Upvotes: 1

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