CODEWITHSUNDEEP
java
user1721548
user1721548

Reputation: 297

how to return random string Arrray Java

I am very new to Java, so this could seem too easy for most people....Is this completely wrong? My question is how to write a method selectRandom(String[] names), which returns a randomly selected name from the given array.

Each name should be selected with equal probability. 

public static String selectRandom(String[] names)    
{    
    String num = names[0]; 
    int[]newArray = new int[names.length];
    for(int i =0; i<names.length;i++)
    {
      Random r = new Random();
      int ranNum= r.nextInt(names.length)+1;
      num = names[ranNum];
    }
    return num;  
}

Upvotes: 2

Views: 3836

Answers (3)

FThompson
FThompson

Reputation: 28687

You can simply generate a random number up to the array size, and get the value at that index.

public static String selectRandom(String[] names) {
    if (name != null && names.length > 0) {
        Random r = new Random();
        return names[r.nextInt(names.length)];
    }
    return null;
}

Upvotes: 5

Emil
Emil

Reputation: 380

Randomly choose an index and return the corresponding String in names. There is a Random class to do get random numbers in java. Also check nextInt method.

public static String selectRandom(String[] names)    
{    
   Random rand = new Random();
   int index = rand.nextInt(names.length);
   return names[index];
}

Upvotes: 0

Russell Gutierrez
Russell Gutierrez

Reputation: 1385

public static String selectRandom(String[] names)    
{    
      Random r = new Random();
      int ranNum= r.nextInt(names.length);
      return names[ranNum];

}

You don't need most of the codes inside your method. Maybe you should try something like this?

Upvotes: 4

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