Reputation: 291
My problem is capture user logout. the code what i have is:
public function onAuthenticationFailure(Request $request, AuthenticationException $exception){
return new Response($this->translator->trans($exception->getMessage()));
}
public function logout(Request $request, Response $response, TokenInterface $token)
{
$empleado = $token->getUser();
$log = new Log();
$log->setFechalog(new \DateTime('now'));
$log->setTipo("Out");
$log->setEntidad("");
$log->setEmpleado($empleado);
$this->em->persist($log);
$this->em->flush();
}
public function onLogoutSuccess(Request $request) {
return new RedirectResponse($this->router->generate('login'));
}
The problem is I can not access the user token TokenInterface
when you are running the logout function?
Upvotes: 9
Views: 7858
Reputation: 3881
Take a look here were you can overwrite any controller of the bundle:
http://symfony.com/doc/current/cookbook/bundles/inheritance.html
Upvotes: 0
Reputation: 371
See http://symfony.com/doc/current/reference/configuration/security.html
security.yml
secured_area:
logout:
path: /logout
**success_handler: logout_listener**
Upvotes: 8
Reputation: 2647
To get token, you must inject with security context.
1. Create class Logout listener, something like this:
namespace Yourproject\Yourbundle\Services;
...
use Symfony\Component\Security\Http\Logout\LogoutSuccessHandlerInterface;
use Symfony\Component\Security\Core\SecurityContext;
class LogoutListener implements LogoutSuccessHandlerInterface {
private $security;
public function __construct(SecurityContext $security) {
$this->security = $security;
}
public function onLogoutSuccess(Request $request) {
$user = $this->security->getToken()->getUser();
//add code to handle $user here
//...
$response = RedirectResponse($this->router->generate('login'));
return $response;
}
}
2. And then in service.yml, add this line:
....
logout_listener:
class: Yourproject\Yourbundle\Services\LogoutListener
arguments: [@security.context]
That's it, may it helps.
Upvotes: 13